C 编程。硬币翻转程序循环没有像我想要的那样工作

Question

所以我应该制作一个抛硬币程序，并且我正确地完成了所有操作，但是我应该使它保持循环，直到用户输入 0。我已经这样做了，但是每次程序循环时，正面和反面的输出不要重置。我运行该程序，它询问我希望硬币翻转多少次，我输入 5。然后它给我说 3 个正面和 2 个反面，然后再次循环问我同样的问题。我再次输入 5，但现在结果是 7 个正面和 3 个反面。但我只要求将其翻转 5 次，因此当我只想要一个新的计数时，它会将旧的头/尾计数添加到新的计数中。我很确定这是一个简单的修复，但请帮忙。代码如下:

for (;;) {

printf("How many times do you want to flip the coin? (Press 0 to exit));
scanf("%d", &toss);                 

if (toss == 0) {
printf("Thank you for using the program!\n");
break;                  //terminates program if toss = 0
}

puts (" ");

for ( counter = 0; counter < toss; counter++ ) 
{
        if (flip( ) == 0)       //call the function flip
        heads++;

        else
        tails++;
}                   //end of for loop

printf( "Heads Was Flipped %d Times\n", heads );
printf( "Tails Was Flipped %d Times\n", tails );

continue;
return 0;

Answer 1

在使用变量之前，必须重置 head 和 tail 的值。这是代码片段。 对于 (;;) {

printf("How many times do you want to flip the coin? (Press 0 to exit));
scanf("%d", &toss);                 

if (toss == 0) {
printf("Thank you for using the program!\n");
break;                  //terminates program if toss = 0
}

puts (" ");
heads = 0;//reset value of heads
tails = 0;//reset value of tails

for ( counter = 0; counter < toss; counter++ ) 
{
        if (flip( ) == 0)       //call the function flip
        heads++;

        else
        tails++;
}                   //end of for loop

printf( "Heads Was Flipped %d Times\n", heads );
printf( "Tails Was Flipped %d Times\n", tails );

continue;
return 0;