c - 我想创建一个摩尔斯电码转换器

Question

在我项目的学校中，我需要将单词转换为摩尔斯电码。

我已经尝试过，但它不起作用:

for (letter = 0; letter > 1000; letter ++)
    {
        scanf ("%s", &word [letter]);

        if (word [letter] == 'a') wordInMorse [4 * letter] = '.-';

        if (word [letter] == 'b') wordInMorse [4 * letter] = '-...';

        if (word [letter] == 'c') wordInMorse [4 * letter] = '-.-.';

        if (word [letter] == 'd') wordInMorse [4 * letter] = '-..';

        if (word [letter] == 'e') wordInMorse [4 * letter] = '.';

        if (word [letter] == 'f') wordInMorse [4 * letter] = '..-.';

        if (word [letter] == 'g') wordInMorse [4 * letter] = '--.';

        if (word [letter] == 'h') wordInMorse [4 * letter] = '....';

        if (word [letter] == 'i') wordInMorse [4 * letter] = '..';

        if (word [letter] == 'j') wordInMorse [4 * letter] = '.---';

        if (word [letter] == 'k') wordInMorse [4 * letter] = '-.-';

        if (word [letter] == 'l') wordInMorse [4 * letter] = '.-..';

        if (word [letter] == 'm') wordInMorse [4 * letter] = '--';

        if (word [letter] == 'n') wordInMorse [4 * letter] = '-.';

        if (word [letter] == 'o') wordInMorse [4 * letter] = '---';

        if (word [letter] == 'p') wordInMorse [4 * letter] = '.--.';

        if (word [letter] == 'q') wordInMorse [4 * letter] = '--.-';

        if (word [letter] == 'r') wordInMorse [4 * letter] = '.-.';

        if (word [letter] == 's') wordInMorse [4 * letter] = '...';

        if (word [letter] == 't') wordInMorse [4 * letter] = '-';

        if (word [letter] == 'u') wordInMorse [4 * letter] = '..-';

        if (word [letter] == 'v') wordInMorse [4 * letter] = '...-';

        if (word [letter] == 'w') wordInMorse [4 * letter] = '.--';

        if (word [letter] == 'x') wordInMorse [4 * letter] = '-..-';

        if (word [letter] == 'y') wordInMorse [4 * letter] = '-.--';

        if (word [letter] == 'z') wordInMorse [4 * letter] = '--..';

        printf ("%s", &wordInMorse [letter]);
   }

运行程序并写入一个单词后，它崩溃了，在“构建消息”选项卡中，每一行都带有 if (word [letter] == '/*letter*/' wordInMorse [4 * letter] = '/*morse*/';) 表示“隐式常量转换中的溢出 [-Woverflow]”和“多字符字符常量 [-Wmultichar]”。

Answer 1

为了指导您，无需做功课，您可以采取以下方法:

• 将 wordInMorse 设为一个包含 26 个字符串指针的全局数组。

• 使用摩尔斯电码字母字符串初始化此数组，因此 wordInMorse 的第一个元素指向字母 A(或 a)的摩尔斯电码。您可以使用初始值设定项来执行此操作吗？还是需要在主程序中编写代码来执行此操作？

• 在主程序中，当用户输入字符串时，查找该数组中的每个字母并使用摩尔斯电码打印该字符串。

要将输入的字母转换为数组中的索引，请将字母变为大写并减去 'A'。

祝你好运!