c# - Entity Framework 6 自定义关系约定

Question

我已阅读 this关于 Entity Framework 6 中约定的文档。但它不包含关系约定。

假设我有以下模型:

[TablePrefix("mst")]
public class Guru
{
    public int Id { get; set; }

    public int? IdKotaLahir { get; set; }

    public virtual Kota KotaLahir { get; set; }
}

我想要属性(property) IdKotaLahir成为导航属性的外键KotaLahir .外键名称是 "Id"+<NavigationPropertyName> .是否可以使用当前版本的 Entity Framework (EF 6 alpha 3)？

Answer 1

在 EF6 中，已接受答案的约定不再有效，因为 IConfigurationConvention 是内部的。处理这种情况的方法是继承ForeignKeyDiscoveryConvention。

public class MyForeignKeyDiscoveryConvention : ForeignKeyDiscoveryConvention
{
    protected override bool MatchDependentKeyProperty(AssociationType associationType, AssociationEndMember dependentAssociationEnd,
        EdmProperty dependentProperty, EntityType principalEntityType, EdmProperty principalKeyProperty)
    {
        string navigationPropertyName = ((System.Reflection.PropertyInfo)dependentAssociationEnd.MetadataProperties.GetValue("ClrPropertyInfo", false).Value).Name;

        // The standard foreign key property to look for is NavigationProperty_PrimaryKeyName (e.g. "TableName_Id"). 
        // Use the below line to remove that underscore.
        //return dependentProperty.Name == navigationPropertyName + principalKeyProperty.Name;

        // Use the following for the IdKotaLahir scenario
        return dependentProperty.Name == "Id" + navigationPropertyName;
    }
}