c - C 中的字符串搜索操作

Question

我想要月份索引的值，但 k 的值是错误的。可以引起？函数有错误但找不到。

#include <stdio.h>
#include <string.h>
#define SIZE 20
int get_month(const char *str, char *array[])
{

int k;
for (k = 0; k < 12; ++k)
    if (!strcmp(array[k], str)
    return k ;
return 0;
}
int main()
{
char s[SIZE];
char *months[] = {"January"," February","March", "April","May","June","July","August ","September", " October"," November","December" };
int result;
printf("enter the month : ");
gets(s);
result = get_month(s,months);
   if (result)
       printf("%s - %d.  is the month of the year.\n", s, result);
      else
    printf("%s invalid\n", s);
return 0;
}

Answer 1

int get_month(const char *str,int char **array)
                               ^

显然你不应该在那里有一个int，字符串数组最好声明为char*[]所以应该是这样

int get_month(const char *str, char *array[])

当你得到索引时，你应该在答案中加 1，因为 C 中的索引从 0 开始，但人类从 1 开始计数。字符串常量中也有一些空格，这会使 strcmp.

<小时/>

完整的工作代码:

#include <stdio.h>
#include <string.h>
#define SIZE 20
int get_month(const char *str, char **array){

    int k;
    for (k = 0; k < 12; ++k)
        if (!strcmp(array[k], str))
            return k+1 ;
    return 0;
}

int main(){
    char s[SIZE];
    char *months[] = {"January","February","March", "April","May","June","July","August","September", "October","November","December" };
    int result;
    printf("enter the month : ");
    gets(s);
    result = get_month(s,months);
    if (result)
        printf("%s - %d.  is the month of the year.\n", s, result);
    else
        printf("%s invalid\n", s);
    return 0;
}

查看此处:Coliru Sample