javascript - 如何在不同 session 中绑定(bind)多个复选框

Question

我有一些带有复选框的数据。现在我想，当任何人点击复选框时，所有选中的数据都应该在 session 中绑定(bind)，并且应该进入下一页。再一次，如果有人点击复选框，那么新点击的数据应该在 session 中。但旧数据不应删除。我试过但没有用，任何事情。请帮忙。

                            <form  name="reservation_form" class="reservation-form mb-0" action="second.php" method="post" novalidate>

            <div class="col-xs-12 col-sm-6 col-md-4">
            <div class="form-group mb-15">
              <input name="name1" class="form-control required " type="text" placeholder="Enter Name" aria-required="true">
            </div>
          </div>
          <div class="col-xs-12 col-sm-6 col-md-4">
            <div class="form-group mb-15">
              <input name="email1" class="form-control required " type="email" placeholder="Enter Email" aria-required="true">
            </div>
          </div>
          <div class="col-xs-12 col-sm-6 col-md-4">
            <div class="form-group mb-15">
              <input name="phone1" class="form-control required " type="text" placeholder="Enter Phone" aria-required="true">
            </div>
          </div>
     <?php
            $query1=mysql_query("select * from lab_location_package_rel where city_id='$selectcity1' AND area_id='$selectarea1' AND lab_id='$selectlab1'") or die (mysql_error());          
             while($value = mysql_fetch_array($query1)) {
                 $mrp=$value['mrp'];
                 $opp=$value['offer_price_perc'];
                 $package_id=$value['package_id'];

                 $per=$mrp*$opp/100;
                 $total=$mrp-$per;

             $query2=mysql_query("select * from package_master where id='$package_id'") or die (mysql_error());
             $value2 = mysql_fetch_array($query2);
             ?>     
                    <li class="list-group-item">
                        <div class="checkbox">
                            <input type="checkbox" id="checkbox" name="name[]" />
                            <label for="checkbox">
                               <b>Package Name:</b> <?php echo $value2['package_title']; ?> <br>
                               <b>MRP:</b>  <strike><?php echo $value['mrp']; ?>  </strike><br>
                               <b>Offer Price:</b>  <?php echo $total; ?>
                            </label>
                        </div>
                        <div class="pull-right action-buttons">
                            <a href="#" class="btn btn-info">View Details</a>
                       </div>
                    </li>
              <?php } ?>     

                </ul>
            </div>
       <input type="button" class="pull-right btn btn-warning" value="Submit">
    </form>

在给定的代码中，当任何人填写所有字段并单击复选框时-

<input type="checkbox" id="checkbox" name="name[]" />
                        <label for="checkbox">
                           <b>Package Name:</b> <?php echo $value2['package_title']; ?> <br>
                           <b>MRP:</b>  <strike><?php echo $value['mrp']; ?>  </strike><br>
                           <b>Offer Price:</b>  <?php echo $total; ?>
                        </label>

然后所有填写的字段和包裹名称、MRP、报价(将为每个复选框选择这些名称)应在 session 中绑定(bind)。

Answer 1

像这样传递并在提交表单时获取值

input type="checkbox"id="checkbox"name="names[]"value="$value2['package_title']">

input type="checkbox"id="checkbox"name="names[]"value="$value['mrp']">

input type="checkbox"id="checkbox"name="names[]"value="$total"/>

$name=$_POST['名字'];$answer = 内爆($name, ",");

然后将名称值分配给 session 。

$_SEESION['name']=$answer;