C# ValueType 等于不比较属性？

Question

以下打印等于:

struct A
{
    int x;
    public A(int _x) { x = _x; }
    public int Y
    {
        get
        {
            Random r = new Random();
            return r.Next(0, 1000);
        }
    }
}

static void Main(string[] args)
{
    A a1 = new A(1),a2 = new A(1);
    if (a1.Equals(a2))
    {
        Console.Write("Equals");
    }
    else
    {
        Console.Write("Different");
    }
}

在这种情况下，有没有办法让 C# 返回 false？意思是，在比较值类型时考虑属性？

Answer 1

写等于然后按“tab”键两次:

// override object.Equals
        public override bool Equals(object obj)
        {


            if (obj == null || GetType() != obj.GetType())
            {
                return false;
            }

            // TODO: write your implementation of Equals() here
            throw new NotImplementedException();
            return base.Equals(obj);
        }

这是一个自动生成的片段。现在您可以尝试类似的操作:

// override object.Equals
        public override bool Equals(object obj)
        {

            // checks for A versus A    
            if (obj == null || GetType() != obj.GetType())
            {
                return false;
            }

            // TODO: write your implementation of Equals() here
            throw new NotImplementedException();
            int compareThis=(A)obj.x;
            return ((A)base).x==compareThis; // maybe casting is not needed
        }