使用 C 的日历 — 无法让它工作

Question

只有当我的第二个输入是周日时，日历才能正常工作。我该如何使其真正空间到正确的日期？有没有什么办法可以让代码更简单、更好、不那么困惑，并且让日历的格式看起来更好看？

#include<stdio.h>

int main()
{
    int i,number,startday;

    //getting user input
    printf("Enter Total Number of Day in the Month:",number);
    scanf("%d", &number);
    printf("Enter Starting Day of The Month (0-6 Sunday-Saturday):",startday);
    scanf("%d", &startday);

    //formatting
    printf("   Sun  Mon  Tue  Wed  Thu  Fri  Sat \n");
    printf("_______________________________________ \n");

    //loop
    for(i=1;i<=number;i++)
      {
        printf("%5d", i);
        if(i == 7 || i == 14 || i == 21 || i == 28)
        {
          printf("\n");
          printf("\n");
        }
      }
    //formatting
    printf("\n_______________________________________");
    return 0;
}

Answer 1

首先阅读并了解 printf() 的真实格式和 scanf() 。

你写:

printf("Enter Total Number of Day in the Month:",number);

应该是:

printf("Enter Total Number of Day in the Month: ");

并且对您的来源进行很少的更改:

#include <stdio.h>

int main(void)
{
    int i, number, startday;

    //getting user input
    printf("Enter Total Number of Day in the Month: ");
    scanf("%d", &number);
    printf("Enter Starting Day of The Month (0-6 Sunday-Saturday): ");
    scanf("%d", &startday);

    //formatting
    printf("  Sun  Mon  Tue  Wed  Thu  Fri  Sat\n");
    printf("______________________________________\n");

    ///fill calendar with proper space "  "
    i=0;
    while (i<startday){
        printf("%5c", ' ');
        i++;
    }

    for(i=1;i<=number;i++){
        printf("%5d", i);

        if((startday+i)%7==0){
            printf("\n\n");
        }
    }

    //formatting
    printf("\n_______________________________________\n");

    return 0;
}

此代码有效，但我建议您检查用户输入具有正确的整数数据类型格式和真实范围简单if (day < 28 || day > 31)或if (startday < 0 || startday > 6) ，并检查每个 scanf()成功，如果没有成功，可能会退出(带有消息)。