c - 为什么我不能得到正确的句子输出？

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有什么问题吗..我听不懂完整的句子

"even(variable) numbers are even".

#include <stdio.h>
void main()
{
    int i = 1, n = 0, even = 0, odd = 0;
    do{
        printf("Type in a Number-");
        scanf("%d", &n);
        if(n % 2 == 0)
            even = even + 1;
        else
            odd = odd + 1;
        i = i + 1;
    }
    while(i <= 10);
    printf("%d", even "numbers are even.");
    printf("%d", odd "numbers are odd.");
}

Answer 1

看来您只需要正确格式化字符串，程序就可以运行:

#include <stdio.h>

int main(void) {
    int i = 1, n = 0, even = 0, odd = 0;
    do {
        printf("Type in a Number-");
        scanf("%d", &n);
        if (n % 2 == 0)
            even = even + 1;
        else
            odd = odd + 1;
        i = i + 1;
    } while (i <= 10);
    printf("%d numbers are even.", even);
    printf("%d numbers are odd.", odd);
    return 0;

}