c# - RX : How to process n buffered items from a sequence then wait t seconds before processing the next n items?

Question

我想弄清楚如何处理序列中的 n 个缓冲项目，然后等待 t 秒再处理下 n 个项目？

这是我尝试使用 Thread.Sleep() 进行的粗略形式。我想避免 Thread.Sleep() 并正确执行。

static void Main(string[] args)
{
    var t = Observable.Range(0, 100000);

    var query = t.Buffer(20);                       

    query.ObserveOn(NewThreadScheduler.Default)
        .Subscribe(x => DoStuff(x));

    Console.WriteLine("Press ENTER to exit");
    Console.ReadLine();

}

static void DoStuff(IList<int> list)
{
    Console.WriteLine(DateTime.Now);

    foreach (var value in list)
    {
        Console.WriteLine(value);
    }

    Thread.Sleep(TimeSpan.FromSeconds(10));
}

任何人都可以帮我找到一种更多的 RX 方法吗？

谢谢

闪光灯

Answer 1

// Instantiate this once, we'll use it in a closure multiple times.
var delay = Observable.Empty<int>().Delay(TimeSpan.FromMilliseconds(10));

// start with a source of individual items to be worked.
Observable.Range(0, 100000)
    // Create batches of work.
    .Buffer(20)
    // Select an observable for the batch of work, and concat a delay.
    .Select(batch => batch.ToObservable().Concat(delay))
    // Concat those together and form a "process, delay, repeat" observable.
    .Concat()
    // Subscribe!
    .Subscribe(Console.WriteLine);

// Make sure we wait for our work to be done.
// There are other ways to sync up, like async / await.
Console.ReadLine();

或者，您也可以使用 async/await 进行同步:

static IObservable<int> delay = Observable.Empty<int>().Delay(TimeSpan.FromMilliseconds(100));

static async Task Run()
{
    await Observable.Range(0, 1000)
        .Buffer(20)
        .Select(batch => batch.ToObservable().Concat(delay))
        .Concat()
        .Do(Console.WriteLine)
        .LastOrDefaultAsync();
}

可观察到的 delay 不是一个绝妙的技巧吗？它之所以有效，是因为 OnCompleted 像 OnNext 一样被延迟了!