c - 操作数类型 ('char' 和 'char *' 不兼容？

Question

有人知道这段代码有什么问题吗？它会出现上面的错误。我正在尝试创建一个程序来生成“随机”字母，并为用户提供最多 6 次猜测该字母的机会。

if ( 播放 != "y"|| 播放 != "Y")

编辑:完整代码

// This function displays game instructions, and returns nothing.
void Instructions();

// This function plays one game, and returns "W" if the player wins
// or "L" if the player runs out of guesses. 
char Play();

//this function prompts the player to make a guess and returns that guess
char getLetter();

//The function returns 1 if the guess matches the solution and returns a 0 if they do not match
char guess();

// This function returns a random letter between "A" and "Z 
char getAnswer();

int CompareLetters(char guess, char answer);

int main()
{ 

    char answer;


    //1. Greet the user and ask if they would like to play a guessing game.
    printf("\nHello there!\nWould like to play a guessing game?Enter Y or N: \n");
    scanf(" %c", &answer);

    if(answer == 'y' || answer == 'Y')
        Instructions();
    {
        printf("\nYou entered Y.  Let's  play!\n");

        do{

        }while (answer == 'y' || answer == 'Y');
    }
    printf("\nMaybe next time.\n");
    printf("\nGoodBye for now.\n");
    return -1;
} 


void Instructions()
{
    printf("I have a capital letter in mind. You have 6 chances to guess which letter I am \nthinking. I will let you know if you are too high or too low.\n");
    printf("After each guess, you will be informed if your guess is too high or too low.\nGood luck!\n");

}

int PlayGuess(char answer)
{
    int NumGuesses=0; int WinOrLose=0;

    while (NumGuesses < MAX_GUESSES && WinOrLose==0);
    {

        //6. If the player guesses wrong for a 6th time, console them and let the program end with a return code of 1.  
        char guess;
        guess = getLetter();
        CompareLetters(guess,answer);
        if(CompareLetters(guess,answer)==1)
        {
            WinOrLose = 1;
        }
        else
        {
            NumGuesses++;
        }
    }
    if (WinOrLose==1)
    {
        return 1;
    }
    else
    {
        return 0;
    }
}

//3. Generate a "random" character between 'A' and 'Z'.  This will be the value the player will try to guess. 
char getLetter()
{
    char guess=0;
    printf("Please enter your letter guess:", guess);
    scanf(" %c",&guess);
    return guess;
}

int CompareLetters(char guess, char answer)
{
    if(guess == answer)
    {
        return 1;
    }
    else
    {
        ////5. If the player does not guess the right answer, display whether the guess is "too high" or "too low". 
        if (guess < answer)
        {
            printf("Your guess is too low.");
        }
        else
        {
            printf("Your guess is too high.");
        }

        {
            printf("\nDo you want to play again? Y or N: \n");

        }
        if ( Play != 'y' &&  Play != 'Y' )
            printf("Thanks for playing.Goodbye!/n");
}

Answer 1

Play 似乎是一个(单个)char，而不是 char 数组。因此，您应该使用 'y' 而不是 "y"。

if ( Play != 'y' || Play != 'Y' )

这里似乎还存在逻辑错误 - 大概您打算使用 && 而不是 ||:

if ( Play != 'y' && Play != 'Y' )

编辑:您现在已经添加了其余的源代码。这里有很多问题，但我将列出一些问题来帮助您入门。

• 对 Instructions() 的调用不在大括号内，因此 Instructions() 将有条件地调用，其余代码将无条件执行 。

  if(answer == 'y' || answer == 'Y')
      Instructions();
  {
      printf("\nYou entered Y.  Let's  play!\n");
  

  这应该是:

  if(answer == 'y' || answer == 'Y')
  {
      printf("\nYou entered Y.  Let's  play!\n");
      Instructions();
  

• 您的 do {} while 语句为空。这也是一个无限循环，因为您的 scanf 答案位于循环之外。

      do{
  
      }while (answer == 'y' || answer == 'Y');
  

  您应该将 scanf 移至循环内部，并添加对 Play() 的调用。

• 与 CompareLetters 中的 Play 进行比较的 if 语句既不正确(没有名为 Play 的变量)，而且错误place(CompareLetters 不应对此负责。)

  您应该将其移至 main，按照我上面提到的方式更新并与 answer 变量进行比较。