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c - 阅读文档并在该文档中查找特定单词

转载 作者:行者123 更新时间:2023-11-30 20:48:53 24 4
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我有以下文档:

WTPZ24 KNHC 032040
TCMEP4

TROPICAL STORM SIMON FORECAST/ADVISORY NUMBER 9
NWS NATIONAL HURRICANE CENTER MIAMI FL EP192014
2100 UTC FRI OCT 03 2014

THERE ARE NO COASTAL WATCHES OR WARNINGS IN EFFECT.

TROPICAL STORM CENTER LOCATED NEAR 18.8N 110.6W AT 03/2100Z
POSITION ACCURATE WITHIN 20 NM

REPEAT...CENTER LOCATED NEAR 18.8N 110.6W AT 03/2100Z
AT 03/1800Z CENTER WAS LOCATED NEAR 18.6N 110.1W

FORECAST VALID 04/0600Z 19.2N 112.2W
MAX WIND 65 KT...GUSTS 80 KT.
64 KT... 10NE 0SE 0SW 10NW.
50 KT... 30NE 30SE 20SW 20NW.
34 KT... 50NE 50SE 40SW 40NW.

FORECAST VALID 04/1800Z 20.0N 114.3W
MAX WIND 75 KT...GUSTS 90 KT.
64 KT... 20NE 10SE 10SW 20NW.

我正在尝试用 C 编写一个程序,该程序将读取该文件并找到单词字符串 FORECast VALID。每当一行有“预测有效”字样时,我希望程序打印该行并在该行之前打印“===>”。对于文档的其余部分,我只希望它简单地打印该行。

程序的最终输出应如下所示:

REPEAT...CENTER LOCATED NEAR 18.8N 110.6W AT 03/2100Z
AT 03/1800Z CENTER WAS LOCATED NEAR 18.6N 110.1W

===>FORECAST VALID 04/0600Z 19.2N 112.2W
MAX WIND 65 KT...GUSTS 80 KT.
64 KT... 10NE 0SE 0SW 10NW.
50 KT... 30NE 30SE 20SW 20NW.
34 KT... 50NE 50SE 40SW 40NW.

===>FORECAST VALID 04/1800Z 20.0N 114.3W
MAX WIND 75 KT...GUSTS 90 KT.
64 KT... 20NE 10SE 10SW 20NW.

我确实有一些代码片段可以逐字打印文档而无需===>,但我只需要帮助如何从行中隔离出FORECAST VALID,以便将===>放在这些行中:

FILE *fr;            /* declare the file pointer */

main()
{
int n;
char line[800];
char buf[255];
fr = fopen ("wtnt23.knhc.201410141453", "rt"); /* open the file for reading */

while(fgets(line, 800, fr) != NULL)
{
sscanf (line, "%s", buf);
if (buf="FORECAST")
{
printf("===>%s",line);
}
else
{
printf("%s",line);
}
fclose(fr); /* close the file prior to exiting the routine */
} /*of main*/

最佳答案

if (buf="FORECAST") 完全错误。它不是比较,您不能使用 =...

复制到 char 数组

你只需要这样做:

while(fgets(line, 800, fr) != NULL)
{
if(0 == strncmp(line, "FORECAST VALID", strlen("FORECAST VALID")) )
{
printf("===>%s",line);
}
else
{
printf("%s",line);
}
}

关于c - 阅读文档并在该文档中查找特定单词,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26372475/

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