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c# - 生成一手扑克牌的所有不同的 7 张牌组合?

转载 作者:行者123 更新时间:2023-11-30 20:46:41 25 4
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我正在尝试生成扑克牌的所有不同组合,如下所述:

Generating all 5 card poker hands

但我总是卡住。当在上述 URL 尝试 NickLarsen 的 C# 答案时,我在第 49 行收到未处理的异常错误。(https://stackoverflow.com/a/3832781/689881)

我想要的很简单:生成所有卡片组合并在一个简单的 .txt 文件中一次打印一行

此外,我实际上想要所有 7 个卡片组合(而不是 5 个)。例如,前两行可能如下所示:

2c2d2h2s3c3d3h
2c2d2h2s3c3d3s

我如何实现这一目标?速度并不那么重要。

下面是 NickLarsen 的代码(经过我的修改)失败了:

using System;
using System.Collections.Generic;
using System.Linq;

namespace ConsoleApplication20
{
struct Card
{
public int Suit { get; set; }
public int Rank { get; set; }
}

class Program
{
static int ranks = 13;
static int suits = 4;
static int cardsInHand = 7;

static void Main(string[] args)
{
List<Card> cards = new List<Card>();
//cards.Add(new Card() { Rank = 0, Suit = 0 });
int numHands = GenerateAllHands(cards);

Console.WriteLine(numHands);
Console.ReadLine();
}

static int GenerateAllHands(List<Card> cards)
{
if (cards.Count == cardsInHand) return 1;

List<Card> possibleNextCards = GetPossibleNextCards(cards);

int numSubHands = 0;

foreach (Card card in possibleNextCards)
{
List<Card> possibleNextHand = cards.ToList(); // copy list
possibleNextHand.Add(card);
numSubHands += GenerateAllHands(possibleNextHand);
}

return numSubHands;
}

static List<Card> GetPossibleNextCards(List<Card> hand)
{
int maxRank = hand.Max(x => x.Rank);

List<Card> result = new List<Card>();

// only use ranks >= max
for (int rank = maxRank; rank < ranks; rank++)
{
List<int> suits = GetPossibleSuitsForRank(hand, rank);
var possibleNextCards = suits.Select(x => new Card { Rank = rank, Suit = x });
result.AddRange(possibleNextCards);
}

return result;
}

static List<int> GetPossibleSuitsForRank(List<Card> hand, int rank)
{
int maxSuit = hand.Max(x => x.Suit);

// select number of ranks of different suits
int[][] card = GetArray(hand, rank);

for (int i = 0; i < suits; i++)
{
card[i][rank] = 0;
}

int[][] handRep = GetArray(hand, rank);

// get distinct rank sets, then find which ranks they correspond to
IEnumerable<int[]> distincts = card.Distinct(new IntArrayComparer());

List<int> possibleSuits = new List<int>();

foreach (int[] row in distincts)
{
for (int i = 0; i < suits; i++)
{
if (IntArrayComparer.Compare(row, handRep[i]))
{
possibleSuits.Add(i);
break;
}
}
}

return possibleSuits;
}

class IntArrayComparer : IEqualityComparer<int[]>
{
#region IEqualityComparer<int[]> Members

public static bool Compare(int[] x, int[] y)
{
for (int i = 0; i < x.Length; i++)
{
if (x[i] != y[i]) return false;
}

return true;
}

public bool Equals(int[] x, int[] y)
{
return Compare(x, y);
}

public int GetHashCode(int[] obj)
{
return 0;
}

#endregion
}

static int[][] GetArray(List<Card> hand, int rank)
{
int[][] cards = new int[suits][];
for (int i = 0; i < suits; i++)
{
cards[i] = new int[ranks];
}

foreach (Card card in hand)
{
cards[card.Suit][card.Rank] = 1;
}

return cards;
}
}
}

最佳答案

这是因为你注释掉了//cards.Add(new Card() { Rank = 0, Suit = 0 });。您的 cards 列表是空的,您的代码找不到空数组的 max - 这是可以预见的。

关于c# - 生成一手扑克牌的所有不同的 7 张牌组合?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26575312/

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