JavaScript 搜索栏在用户输入后显示结果

Question

我有一个显示我的本地文件列表的网页，我有一个搜索栏，它遍历文件列表并突出显示第一个匹配项。

但是，如何才能仅在用户搜索文件名时显示文件。因此，我不想显示所有文件，而是只希望返回符合搜索条件的文件。

如果有人能在这方面提供帮助，PHP、JavaScript、jQuery 完全是一个选择。

测试执行器.php:

<?php
$path = '/var/www/html/'; //get list of files
$files = scandir($path);

//display the links

foreach($files as $file) {
     if($file != '.' && $file != '..') {
        echo '<div><a href="readfile.php?file='.urlencode($file).'"> '.$file.'</a></div>';
     }
}

?>

读取文件.php:

<?php
 // PHP script to allow the file to be downloaded
$filename = $_GET['file'];

if (file_exists($filename)) {
  header('Content-Description: File Transfer');
  header('Content-Type: application/octet-stream');
  header('Content-Disposition: attachment; 
filename="'.basename($filename).'"');
  header('Expires: 0');
  header('Cache-Control: must-revalidate');
  header('Pragma: public');
  header('Content-Length: ' . filesize($file));
  readfile($filename);
  exit;
 }
 ?>

    //JavaScript for searchbar     function FindNext() {     var str = document.getElementById ("livesearch").value;            if (str == "") {                alert ("Please enter some text to search!");                return;            }     var supported = false;            var found = false;            if (window.find) {        // Firefox, Google Chrome, Safari                supported = true;                    // if some content is selected, the start position of the search                     // will be the end position of the selection                found = window.find (str);            } else {                if (document.selection && document.selection.createRange) { // Internet Explorer, Opera before version 10.5                    var textRange = document.selection.createRange ();                    if (textRange.findText) {   // Internet Explorer                        supported = true;                            // if some content is selected, the start position of the search                             // will be the position after the start position of the selection                        if (textRange.text.length > 0) {                            textRange.collapse (true);                            textRange.move ("character", 1);                        }                        found = textRange.findText (str);                        if (found) {                            textRange.select ();                        }                    }                }            }            if (supported) {                if (!found) {                    alert ("The following text was not found:\n" + str);                }            }            else {                alert ("Your browser does not support this example!");            }        }    

Answer 1

这是最简单的想法。

前端

index.html

$('input').keydown(function(e) {
  var str = $(this).val();
  alert(str);
  $.get("/search.php?query=" + str, function(data) {
    $('.result').html(data);
  });
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<h3>File search and download</h3>
<input name="filename" placeholder="file name" class="kw"/>
<div class="result">
</div>

后端

搜索.php

<?php
// You need code search file
// after search $files
$str = '';
foreach($files as file) {
    $str .= '<a href="readfile.php?file=...">'.$file.'</a> <br>'
}
return $str;
?>

读取文件.php

    <?php
     // PHP script to allow the file to be downloaded
    $filename = $_GET['file'];

    if (file_exists($filename)) {
      header('Content-Description: File Transfer');
      header('Content-Type: application/octet-stream');
      header('Content-Disposition: attachment; 
    filename="'.basename($filename).'"');
      header('Expires: 0');
      header('Cache-Control: must-revalidate');
      header('Pragma: public');
      header('Content-Length: ' . filesize($file));
      readfile($filename);
      exit;
     }
     ?>