c - 多项式的链表表示

Question

我必须编写一个程序来对两个多项式求和。为此，首先，我正在编写一个程序来获取两个多项式并打印它们。

我的程序是这样的:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

struct node
{
    int power;
    int coef;
    struct node *link;
};



int input( struct node *Phead);
int display( struct node *Phead);

int main()
{
    struct node *Phead= malloc(sizeof(struct node)),*Qhead = malloc(sizeof(struct node));
    input(Phead);
    display(Phead);

    input(Qhead);
    display(Qhead);

    return 0;
}

int input( struct node *Phead)
{
    //Phead 
    //Qhead = malloc(sizeof(struct node));
    int value;

    printf("\n\t\tEntry of polynomial:\n");

    printf("Enter the coefficient: ");
    scanf("%d",&Phead->coef);
    printf("Enter the power: ");
    scanf("%d",&Phead->power);
    Phead->link = NULL ;

    printf("Enter the coefficient,( 0 to break ): ");
    scanf("%d", &value);

    while ( value != 0 )
    {
        struct node *new_node = malloc(sizeof(struct node ));

        new_node -> coef = value;

        printf("Enter the power: ");
        scanf("%d",&new_node->power);
        new_node->link = Phead;
        Phead = new_node; 
        //printf("%d",Phead->power);
        printf("Enter the coefficient,( 0 to break ): ");
        scanf("%d", &value);
    }
    return 0;
}

int display( struct node *Phead)
{
    struct node *temp = Phead;
    //printf("I am in display.\n");

    while ( temp != NULL )
    {
        //printf("I am in while.\n");
        printf("%d * x ^ %d + ",temp->coef,temp->power);
        temp=temp->link;
    }
    //printf("%d * x ^ %d + ",temp->coef,temp->power);
    //printf("0");

    return 0;
}

我无法打印多项式。问题出在临时变量上。请帮我解决这个问题。

Answer 1

问题出在你的这部分代码上:

new_node->link = Phead;
Phead = new_node; 

解决方法如下:

Phead->link = new_node;
Phead = new_node;