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C - 将字符串添加到数组 x 中并将其从数组 y 中删除

转载 作者:行者123 更新时间:2023-11-30 20:43:20 24 4
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我创建了一个游戏平台,我想交易一些游戏。

因此,我设法编写了一个代码,用户可以在其中将他的游戏出售到市场,而另一个用户如果有信用,则可以随时购买它。为了做到这一点,我需要将已售出的游戏添加到买方的库中并将其从卖方的库中删除,但我缺少一些东西。

我写的代码或多或少是:

#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#include <string.h>
#include <unistd.h>
#include <math.h>

typedef struct {
char username [15];
char email [25];
char surname [20];
char name [20];
char sex;
int hours;
int level;
float credit;
char* library[20];
} User;

typedef struct {
char id_code [7];
char name [35];
char developer [30];
char category [15];
float price;
int pegi;
char seller [15];
} Game;

...

int main() {
int max=1, z=0, u=0;
User signed_up [max];
Game database [20], marketplace [20];
...
system("pause");
return 0;
}

...

void buy_game (int max, int *pz, int *pu, User signed_up[], Game database[], Game marketplace[]) {
int i=0, j=0, h=0, y=0, x=0, a=0, b=0, w=0, v=0, c=0;
bool game_found=false, user_found=false, not_owned_game=false;
char input_game [35], input_user[15];

v=*pz;
w=*pu;

...

printf("\n%*sInserisci username dell'utente con cui acquistare il gioco: ", 26, "");
fflush(stdin);
scanf("%s", input_user);
printf("\n");

for(i=0;i<max-1;i++) {
if (strcmp(input_user, signed_up[i].username)==0) {
user_found=true;

printf("%*sInserisci nome del gioco da acquistare: ", 26, "");
fflush(stdin);
fgets(input_game, sizeof (input_game), stdin);
input_game[strlen(input_game)-1]='\0';
printf("\n");

for (j=0;j<w;j++) {
if (strcmp(input_game, marketplace[j].name)==0) {
game_found=true;

for (h=0;h<max-1;h++) {
if (strcmp(signed_up[h].username, marketplace[j].seller)==0) {
for (y=0;y<v;y++) {
if (strcmp(marketplace[j].name, signed_up[h].library[y])==0) {
for (a=0;a<v;a++) {
if (strcmp(marketplace[j].name, signed_up[i].library[a])!=0) {
not_owned_game=true;

if (marketplace[j].price<=signed_up[i].credit) {

printf("\n%*sOperazione avvenuta con successo!\n", 26, "");
signed_up[i].credit=signed_up[i].credit-marketplace[j].price;
printf("\n%*sIl credito attuale dell'utente %s %c: EUR %.2f\n", 26, "", signed_up[i].username, 138, signed_up[i].credit);
signed_up[h].credit=signed_up[h].credit+marketplace[j].price;
printf("\n%*sIl credito attuale dell'utente %s %c: EUR %.2f\n\n\n", 26, "", signed_up[h].username, 138, signed_up[h].credit);

signed_up[i].library[y]=marketplace[j].name;
//add game to buyer's library

do {
signed_up[h].library[y]=signed_up[h].library[y+1];
y+=1;
} while (y<v-1);
signed_up[h].library[v-1]="";
//remove game from seller's library

do {
marketplace[j]=marketplace[j+1];
j+=1;
} while (j<w-1);
*pu-=1;
//remove game from marketplace
} else {
printf("%*sCredito acquirente insufficiente! Si prega di ricaricare il conto.\n\n", 26, "");
}
}
} if (not_owned_game==false) {
printf("%*sGioco inserito gi%c presente nella libreria dell'utente!\n\n\n", 26, "", 133);
}
}
}
}
}
}
} if (game_found==false) {
printf("%*sGioco inserito non presente nel marketplace!\n\n\n", 26, "");
}
}
} if (user_found==false) {
printf("\n%*sUsername inserito non presente nel database!\n\n\n", 26, "");
}
}

我遇到的问题是,当我检查用户的库时,程序有一个奇怪的行为,因为它不能正确记住买家和卖家的库;事实上,该程序拒绝显示其库中的任何游戏。

最佳答案

数组具有固定大小,因此您无法删除条目。您可以覆盖,也可以改变位置,这两种情况都可能导致数组中不再存在特定值。

因此,请考虑当固定大小数组在逻辑上少包含一项时您希望它是什么样子,因为您实际上无法缩小它。然后思考需要进行哪些更改才能将数组突变为所需的状态,最后编写代码。

关于C - 将字符串添加到数组 x 中并将其从数组 y 中删除,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46223910/

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