javascript - 组合此集合的最有效方法是什么？

Question

给定以下集合，将这些数据按房间分组并使“名称”成为数组的最佳方法是什么？排除重复项，并且不想使用调用键“名称”来使其在有更多字段时更具动态性:

var roomAssignments = [{
    room: 'Foo',
    name: 'Fooname',
    other: 'Other'
},{
    room: 'Bar',
    name: 'Barname',,
    other: 'OtherBar'
},{
    room: 'Foo',
    name: 'Baz',,
    other: 'Other'
},{
    room: 'Foo',
    name: 'Baz',,
    other: 'Other'
},{
    room: 'Foo',
    name: 'Bat',,
    other: 'Other'
}];

期望的输出:

[{
    room: 'Foo',
    name: [ 'Fooname', 'Baz', 'Bat' ],
    other: ['Other']
}, {
    room: 'Bar',
    name: [ 'Barname' ],
    other: ['OtherBar']
}]

我目前正在使用 lodash，并且更喜欢它或纯 javascript。我想我已经关注这个太久了，我有大约 30 个键需要组合成数组，我正在寻找将所有键动态组合成数组的最有效方法。

Answer 1

您可以使用函数 reduce 和函数 includes 来丢弃重复值。

var roomAssignments = [{    room: 'Foo',    name: 'Fooname',    other: 'Other'},{    room: 'Bar',    name: 'Barname',    other: 'OtherBar'},{    room: 'Foo',    name: 'Baz',    other: 'Other'},{    room: 'Foo',    name: 'Baz',    other: 'Other'},{    room: 'Foo',    name: 'Bat',    other: 'Other'}],
    result = Object.values(roomAssignments.reduce(function(a, c) {
  if (a[c.room]) {
    Object.keys(c).forEach(function(k) {
      if (k === 'room') return;      
      if (a[c.room][k]) {
        if (!a[c.room][k].includes(c[k])) a[c.room][k].push(c[k]);
      } else a[c.room][k] = [c[k]];
    });
  } else { 
    a[c.room] = { room: c.room };
    Object.keys(c).forEach(function(k) {
      if (k === 'room') return;      
      a[c.room][k] = [c[k]];
    });
  }
  
  return a
}, {}));

console.log(result);

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