c++ - 从函数初始化对象地址

Question

这个问题已经有答案了:

Having a function change the value a pointer represents in C (7 个回答)

已关闭 9 年前。

您能帮我了解如何从函数更新指针地址吗？

我在我的 C++ 项目中使用了 C 库 (libmpdclient)。

来自 C 库:

const struct mpd_song *     mpd_entity_get_song (const struct mpd_entity *entity)

我的标题原型(prototype):

typedef struct {
  struct mpd_song * m_song; // from a C library
  ....                      // not important stuff
}
void GetSongInfo(const struct mpd_song * m_song, char* uri);

我的代码:

void MpdPlayer::GetSongInfo(const struct mpd_song * song, char* uri)
{
  struct mpd_entity * entity;
  mpd_send_list_meta(m_connection, *uri);
  song = mpd_entity_get_song(entity);
  mpd_entity_free(entity);

  printf("song adress: %p\n", song); // OK the result is 0x370e6e0
  printf("song duration: %u\n", mpd_song_get_duration(song)); // OK I can get the time
}

GetSongInfo(myStruct->m_song, m_fileuri);
printf("myStruct->m_song adress : %p\n", si->m_song); // FAIL the result is : nil

我尝试了很多，但我认为我迷失了:/

Answer 1

struct mpd_song * MpdPlayer::GetSongInfo(char* uri)
{
  struct mpd_entity * entity;
  mpd_send_list_meta(m_connection, *uri);
  struct mpd_song * song = mpd_entity_get_song(entity);
  mpd_entity_free(entity);

  printf("song adress: %p\n", song);
  printf("song duration: %u\n", mpd_song_get_duration(song));

  return song;
}

myStruct->m_song = GetSongInfo(m_fileuri);