c - 为什么这个按位运算符返回负数？

Question

我刚刚阅读了有关按位运算符的教程，但我不明白为什么这个数字是 -61。

unsigned int a = 60;    /* 60 = 0011 1100 */  
unsigned int b = 13;    /* 13 = 0000 1101 */
int c = 0; 
c = ~a;          /*-61 = 1100 0011 */
printf("Line 4 - Value of c is %d\n", c );

11000011不应该是195吗？ (128+64+2+1)

http://www.tutorialspoint.com/cprogramming/c_bitwise_operators.htm

Answer 1

不，不应该这样!

您可能希望对所有参数使用unsigned char

unsigned char a = 60;
unsigned char b = ~a;
char c = ~a;
printf("b=%d\nc=%d\n", b, c);

给出输出:

b=195
c=-61