javascript - 基于Javascript中的多个条件对数组进行排序

Question

我有一个包含对象的数组，如下所示:

[{
    id: 34,
    users: [{
        name: 'Lisa',
        age: 23
    }, {
        name: 'Steven',
        age: 24
    }]
} ,{
    id: 35,
    users: [{
        name: 'John',
        age: 23,
    }, {
        name: 'Steven',
        age: 24
    }, {
        name: 'Charlie',
        age: 24
    }]
}, {
    id: 36,
    users: [{
        name: 'Lisa',
        age: 23,
    }, {
        name: 'John',
        age: 24
    }, {
        name: 'Homer',
        age: 24
    }, {
        name: 'Charlie',
        age: 24
    }]
}, {
    id: 37,
    users: [{
        name: 'Lisa',
        age: 23
    }, {
        name: 'John',
        age: 24
    }]
}]

我想根据几个条件(优先)对数组进行排序:首先，我想要用户名称为“John”和“Lisa”且用户数小于 3 的对象其次，我想要对象的用户名称为“John”和“Lisa”，而不管参与者的数量然后剩下的对象

因此，我举的例子中的数组将变为:

[{
    id: 37,
    users: [{
        name: 'Lisa',
        age: 23
    }, {
        name: 'John',
        age: 24
    }]
}, {
    id: 36,
    users: [{
        name: 'Lisa',
        age: 23
    }, {
        name: 'John',
        age: 24
    }, {
        name: 'Homer',
        age: 24
    }, {
        name: 'Charlie',
        age: 24
    }]
}, {
    id: 34,
    users: [{
        name: 'Lisa',
        age: 23
    }, {
        name: 'Steven',
        age: 24
    }]
}, {
    id: 35,
    users: [{
        name: 'John',
        age: 23
    }, {
        name: 'Steven',
        age: 24
    }, {
        name: 'Charlie',
        age: 24
    }]
}]

我现在有这个，它根据参与者的姓名和数量正确排序。但是如果参与者的数量不匹配，那么它就不会关心要排序的名字，这是错误的:

 const names = ['John', 'Lisa']
 unorderedLeagues.sort((a, b) => {
    const aUserIncluded = every(names, priorityName =>
      some(a.users, { name: priorityName }),
    );
    const bUserIncluded = every(names, priorityName =>
      some(b.users, { name: priorityName }),
    );

    return (
      (bUserIncluded && b.users.length <= 3) -
      (aUserIncluded && a.users.length <= 3)
    );
  });

我应该如何修改此排序以执行我描述的优先级类型？

Answer 1

您可以使用 bool 值来检查所需名称是否在 users 中。然后取长度为好还是不取。

var array = [{ id: 34, users: [{ name: 'John', age: 23}, { name: 'Steven', age: 24}] }, { id: 35, users: [{ name: 'John', age: 23}, { name: 'Steven', age: 24}, { name: 'Charlie', age: 24}] }, { id: 36, users: [{ name: 'Lisa', age: 23}, { name: 'John', age: 24}, { name: 'Homer', age: 24}, { name: 'Charlie', age: 24}] }, { id: 37, users: [{ name: 'Lisa', age: 23}, { name: 'John', age: 24}] }],
    find = ['John', 'Lisa'];

array.sort(function (a, b) {
    var aAll = find.every(n => a.users.find(({ name }) => name === n)),
        bAll = find.every(n => b.users.find(({ name }) => name === n));

    return (bAll && b.users.length === 2) - (aAll && a.users.length === 2) || bAll - aAll;
});

console.log(array);

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