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调用 free 命令来释放内存会使我的程序崩溃。为什么?

转载 作者:行者123 更新时间:2023-11-30 20:34:38 24 4
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我编写了一个使用维吉尼亚密码加密和解密消息的程序。加密部分工作正常,问题是解密部分:当我想使用 free() 释放 char* 时,我的程序崩溃了。当我不释放它时,程序运行良好并且不会崩溃。程序代码如下:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <stdarg.h>

int main(void) {
int choice, check, error;
char ch;
printf("What do you want to do?\n"
"1...Decode a message that is saved in a ciphertext.txt file.\n"
"2...Encode a message and save it in a ciphertext.txt file.\n");
do {
error = 0;
check = scanf("%d%c", &choice, &ch);
if (check != 2 || ch != '\n' || choice < 1 || choice > 2) {
printf("Error: Invalid input!\n");
error = 1;
}
fflush(stdin);
} while (error);
if (choice == 2) {
FILE *fp = fopen("ciphertext.txt", "w+");
char buffer[1000];
char *p, *q, *r;
char *encryption_text;
char *encrypted;
char *decrypted;
printf("What are bad characters?\n");
printf("-Everything except A-Z and a-z.\n");
printf("Plaintext: ");
gets(buffer);
decrypted = (char *)malloc(strlen(buffer));
strcpy(decrypted, buffer);
printf("Key: ");
gets(buffer);
encryption_text = (char *)malloc(strlen(buffer));
strcpy(encryption_text, buffer);
encrypted = (char *)malloc(strlen(decrypted));
strcpy(encrypted, decrypted);
putchar('\n');
p = decrypted;
q = encryption_text;
r = encrypted;
if (strlen(q) > strlen(p)) {
printf("The key has to be shorter or equal length as the plaintext.");
return 0;
}
while (*p != '\0') {
if (!(*p >= 'A' && *p <= 'Z') && !(*p >= 'a' && *p <= 'z')) {
printf("Bad characters.");
return 0;
}
if (*q == '\0') {
q = encryption_text;
} else if (!(*q >= 'A' && *q <= 'Z') && !(*q >= 'a' && *q <= 'z')) {
printf("Bad characters.");
return 0;
}
if (*p >= 'a' && *p <= 'z') *p -= ' ';
if (*q >= 'a' && *q <= 'z') *q -= ' ';
*r = (*p - 'A' + *q - 'A') % 26 + 'A';
p++;
q++;
r++;
}
printf("Ciphertext: ");
puts(encrypted);
fputs(encryption_text, fp);
fprintf(fp, ";");
fputs(encrypted, fp);
free(decrypted);
free(encrypted);
free(encryption_text);
fclose(fp);
} else {
FILE *fp = fopen("ciphertext.txt", "r+");
char buffer[1000];
char *encryption_text;
char *encrypted;
char *decrypted;
char delimeter[2] = ";";
char *token;
char *p, *q, *r;
fgets(buffer, 1000, fp);
encrypted = (char *)calloc(strlen(buffer) * sizeof(char), sizeof(char));
encryption_text = (char *)calloc(strlen(buffer) * sizeof(char), sizeof(char));
token = strtok(buffer, delimeter);
strcpy(encryption_text, token);
encrypted = strrchr(buffer, '\0');
if (encrypted != NULL) {
strcpy(encrypted, encrypted + 1);
}
decrypted = (char *)calloc(strlen(buffer) * sizeof(char), sizeof(char));
for (p = decrypted, q = encryption_text, r = encrypted;
*r != '\0'; p++, r++, q++) {
if (*q == '\0') {
q = encryption_text;
}
*p = (*r - 'A' - (*q - 'A') + 26) % 26 + 'A';
}
printf("Plaintext: ");
puts(decrypted);
printf("Key: ");
puts(encryption_text);
printf("Ciphertext: ");
puts(encrypted);
if (decrypted) free(decrypted);
if (encrypted) free(encrypted);
if (encryption_text) free(encryption_text);
fclose(fp);
}
return 0;
}

我希望你能告诉我为什么会崩溃。谢谢!

最佳答案

崩溃的主要原因可能是以下一行,

    encrypted = strrchr(buffer, '\0');

其中您让encrypted指向由局部变量buffer表示的内存中的某个位置。这很可能是堆栈上的内存,但至少该内存还没有通过 malloc/calloc 分配。

因此稍后释放加密很可能会在释放操作时崩溃。

顺便说一句:正如评论中提到的,在使用 strcpy 时重新考虑您的 malloc/calloc 语句,以便为终止 '\0' 留出空间.

此外,请注意 strrchr(buffer, '\0') 返回一个指向 buffer 中包含的字符串末尾的指针;使用 strcpy 从终止 '\0' 之后的位置复制内存可能很关键,因为不能保证会有第二个字符串终止字符。

encrypted = strrchr(buffer, '\0');
if (encrypted != NULL) {
strcpy(encrypted, encrypted + 1);
}

关于调用 free 命令来释放内存会使我的程序崩溃。为什么?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41925218/

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