c# - 正则表达式:如何捕获重复捕获组中的所有迭代

Question

我希望这些 C# 行:

var regex = new Regex("A(bC*)*");
var match = regex.Match("AbCCbbCbCCCCbbb");
var groups = match.Groups;

返回类似的东西:

["AbCCbbCbCCCCbbb", "A", "bCC", "b", "bC", "bCCC", "b", "b", "b"]

但它只返回最后捕获的匹配项:

["AbCCbbCbCCCCbbb", "b"]

Here Regex101 还显示以下内容作为警告:

A repeated capturing group will only capture the last iteration. Put a capturing group around the repeated group to capture all iterations or use a non-capturing group instead if you're not interested in the data

我应该如何更改我的正则表达式模式？

Answer 1

如果您还想捕获 A，只需将其用括号括起来:new Regex("(A)(bC*)*")。查看regex demo .

然后，收集你在 CaptureCollection 中得到的所有值:

var regex = new Regex("(A)(bC*)*");
var match = regex.Matches("AbCCbbCbCCCCbbb")
     .Cast<Match>()
     .SelectMany(x => x.Groups.Cast<Group>()
          .SelectMany(v => v.Captures
              .Cast<Capture>()
              .Select(t => t.Value)
          )
     )
     .ToList();
 foreach (var s in match)
     Console.WriteLine(s);

参见 C# demo