- html - 出于某种原因,IE8 对我的 Sass 文件中继承的 html5 CSS 不友好?
- JMeter 在响应断言中使用 span 标签的问题
- html - 在 :hover and :active? 上具有不同效果的 CSS 动画
- html - 相对于居中的 html 内容固定的 CSS 重复背景?
我想允许用户输入可变金额,然后将该金额与我的百分比数组进行比较。然后在我的百分比数组中显示等于或大于用户输入的数字的所有金额。我也想以较低的金额来做这件事,但我认为它们应该是相同的。如果有人可以提供任何见解,我将不胜感激!代码将附在下面..(如果我可以澄清任何事情,请告诉我)
/*
10/31/2017
FOOTBALL STATS
*/
#include <stdio.h>
#define NUM_TEAM 30
#define LEN_NAME 40
void displayWelcome(void);
void calcPercent(double percentages[], int elements, int wins[], int losses[], int ties[]);
void showAll (char name[], char league[], char division[], int wins, int losses, int ties, double percentages);
void displayExit(void);
int main (void)
{
//Display welcome message
displayWelcome();
char name[NUM_TEAM][LEN_NAME] = {0};
char division[NUM_TEAM][LEN_NAME] = {0};
char league[NUM_TEAM][LEN_NAME] = {0};
char line[LEN_NAME];
char menu, again;
int wins[NUM_TEAM] = {0};
int losses[NUM_TEAM] = {0};
int ties[NUM_TEAM] = {0};
int i = 0, count, sum, percentQuery;
double percentages[NUM_TEAM] = {0};
;
FILE * filePtr;
filePtr = fopen("C:\\Users\\thoma\\NFLTeams.txt", "r");
if (filePtr == NULL)
{
printf("Unable to open file\n");
}
else
{
while (i < NUM_TEAM && fgets( line, sizeof(line), filePtr) != NULL)
{
sscanf(line, "%s%s%s%i%i%i",name[i], league[i], division[i], &wins[i], &losses[i], &ties[i]);
i++;
}
fclose(filePtr);
count = i;
}
//^ end reading in file
//Calculate win percentages
calcPercent( percentages, count, wins, losses, ties);
//Main menu loop
do
{
//Ask user how they would like to search
printf("Please choose an option from the following menu:"
"\n-Enter 'a' to display all information contained in the database"
"\n-OR Enter 'b' to search by league"
"\n-OR Enter 'c' to search by division"
"\n-OR Enter 'd' to search by wins above a certain percentage"
"\n-OR Enter 'e' to search by wins below a certain percentage: ");
scanf("\n%c", &menu);
//If user chooses a
if (menu == 'a')
{
//Display all of database
for (i = 0; i <= count - 1; i = i + 1)
{
showAll(name[i], league[i], division[i], wins[i], losses[i], ties[i], percentages[i]);
}
}
//If user chooses b
else if (menu == 'b')
{
// Propmt user to choose AFC or NFC
printf("\nPlease choose from the following menu:\nEnter 'a' to search for teams in the AFC league \nOR enter 'b' to search for teams in the NFC league: ");
// scan for what the user entered
scanf("\n%c", &menu);
//Display option for AFC
if (menu == 'a')
{
for (i = 0; i < count; i = i + 1 )
{
if (strcmp (league[i], "AFC") == 0)
{
printf("Here are the standings for the teams in the AFC division:\n");
printf("Team Name: %s \nLeague: %s\nDivision: %s\nWins: %i Losses: %i Ties: %i\nWin Rate: %.2lf%%\n\n", name[i], league[i], division[i], wins[i], losses[i], ties[i], percentages[i]);
}
}
}
else
//Display option for NFC
{
for (i = 0; i < count; i = i + 1 )
{
if (strcmp (league[i], "NFC") == 0)
{
printf("Here are the standings for the teams in the NFC division:\n");
printf("Team Name: %s \nLeague: %s\nDivision: %s\nWins: %i Losses: %i Ties: %i\nWin Rate: %.2lf%%\n\n", name[i], league[i], division[i], wins[i], losses[i], ties[i], percentages[i]);
}
}
}
}
//If user chooses c
else if (menu == 'c')
{
printf("\nPlease choose an option from the following menu: \nEnter 'a' if you would like to search for North division standings\n"
"OR enter 'b' to search for East division standings\nOR enter 'c' to search for South division standings\nOR enter"
" 'd' to search for West division standings: ");
scanf("\n%c", &menu);
if (menu == 'a')
{
for (i = 0; i < count; i = i + 1 )
{
if (strcmp (division[i], "North") == 0)
{
printf("Here are the standings for the teams in the North division:\n");
printf("Team Name: %s \nLeague: %s\nWins: %i Losses: %i Ties: %i\nWin Rate: %.2lf%%\n\n", name[i], league[i], wins[i], losses[i], ties[i], percentages[i]);
}
}
}
else if (menu == 'b')
{
for (i = 0; i < count; i = i + 1 )
{
if (strcmp (division[i], "East") == 0)
{
printf("Here are the standings for the teams in the East division:\n");
printf("Team Name: %s \nLeague: %s\nWins: %i Losses: %i Ties: %i\nWin Rate: %.2lf%%\n\n", name[i], league[i], wins[i], losses[i], ties[i], percentages[i]);
}
}
}
else if (menu == 'c')
{
for (i = 0; i < count; i = i + 1 )
{
if (strcmp (division[i], "South") == 0)
{
printf("Here are the standings for the teams in the South division:\n");
printf("Team Name: %s \nLeague: %s\nWins: %i Losses: %i Ties: %i\nWin Rate: %.2lf%%\n\n", name[i], league[i], wins[i], losses[i], ties[i], percentages[i]);
}
}
}
else if (menu == 'd')
{
for (i = 0; i < count; i = i + 1 )
{
if (strcmp (division[i], "West") == 0)
{
printf("Here are the standings for the teams in the West division:\n");
printf("Team Name: %s \nLeague: %s\nWins: %i Losses: %i Ties: %i\nWin Rate: %.2lf%%\n\n", name[i], league[i], wins[i], losses[i], ties[i], percentages[i]);
}
}
}
}
//if user chooses d
else if (menu == 'd')
{
/* UNFINISHED.. COULD NOT FIGURE OUT SYNTAX
My goal was to compare my percentages array to the value that the user inputted (which was stored in the variable 'percentQuery' and display values that were greater than or equal to my percent
Query
printf("In this menu, you may search for a win percentage above a certain amount.\n"
"Please enter the amount you would like to search ABOVE: ");
scanf("\n%d", &percentQuery);
for (i = 0; i < count; i = i + 1 )
{
//I could not figure out the syntax for comparing to see if it was greater than or equal to percentQuery
if (strcmp (percentages[i], percentQuery) == 0)
{
printf("Here are the standings for the teams with a win percent above %i%%"), percentQuery;
printf("Team Name: %s \nLeague: %s\nWins: %i Losses: %i Ties: %i\nWin Rate: %.2lf%%\n\n", name[i], league[i], wins[i], losses[i], ties[i], percentages[i]);
}
}*/
}
//if user chooses e
else if (menu == 'e')
{
/* UNFINISHED.. COULD NOT FIGURE OUT SYNTAX
My goal was to compare my percentages array to the value that the user inputted (which was stored in the variable 'percentQuery' and display values that were less than or equal to my percent
Query
printf("In this menu, you may search for a win percentage below a certain amount.\n"
"Please enter the amount you would like to search BELOW: ");
scanf("\n%d", &percentQuery);
for (i = 0; i < count; i = i + 1 )
{
// I could not figure out the syntax for comparing to see if it was less than or equal to percentQuery
if (strcmp (percentages[i], percentQuery) == 0)
{
printf("Here are the standings for the teams with a win percent below %i%%"), percentQuery;
printf("Team Name: %s \nLeague: %s\nWins: %i Losses: %i Ties: %i\nWin Rate: %.2lf%%\n\n", name[i], league[i], wins[i], losses[i], ties[i], percentages[i]);
}
}*/
}
//Prompt user for replay of main menu
printf("\nWould you like to return to the main menu?\n"
"Enter (y)es or (n)o: ");
scanf("\n%c", &again);
}
while (again == 'y');
//whatever the user types in, strcmp to our data base and set it equal to that.
displayExit();
return 0;
}
void displayWelcome(void)
{
printf("Welcome to my Football Stats.\n\n");
}
void calcPercent(double percentages[], int count, int wins[], int losses[], int ties[])
{
int i, sum;
for (i = 0; i <= count -1; i = i + 1)
{
sum = wins[i] + losses[i] + ties[i];
percentages[i] = ((double) wins[i] / sum) * 100;
}
}
void showAll (char name[], char league[], char division[], int wins, int losses, int ties, double percentages)
{
printf("Team Name: %s \nLeague: %s\nDivision: %s\nWins: %i Losses: %i Ties: %i\nWin Rate: %.2lf%%\n\n", name, league, division, wins, losses, ties, percentages);
}
void displayExit(void)
{
printf("\nThese results were brought to you by.");
}
最佳答案
只需使用 >=
“高于或等于”运算符和 <
对于“以下”:
if (percentages[i] >= percentQuery) {
/* ... */
}
percentages
是 double 组,而不是字符串。
关于c - 有没有类似于字符串比较但针对整数的函数?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47209767/
C语言sscanf()函数:从字符串中读取指定格式的数据 头文件: ?
最近,我有一个关于工作预评估的问题,即使查询了每个功能的工作原理,我也不知道如何解决。这是一个伪代码。 下面是一个名为foo()的函数,该函数将被传递一个值并返回一个值。如果将以下值传递给foo函数,
CStr 函数 返回表达式,该表达式已被转换为 String 子类型的 Variant。 CStr(expression) expression 参数是任意有效的表达式。 说明 通常,可以
CSng 函数 返回表达式,该表达式已被转换为 Single 子类型的 Variant。 CSng(expression) expression 参数是任意有效的表达式。 说明 通常,可
CreateObject 函数 创建并返回对 Automation 对象的引用。 CreateObject(servername.typename [, location]) 参数 serv
Cos 函数 返回某个角的余弦值。 Cos(number) number 参数可以是任何将某个角表示为弧度的有效数值表达式。 说明 Cos 函数取某个角并返回直角三角形两边的比值。此比值是
CLng 函数 返回表达式,此表达式已被转换为 Long 子类型的 Variant。 CLng(expression) expression 参数是任意有效的表达式。 说明 通常,您可以使
CInt 函数 返回表达式,此表达式已被转换为 Integer 子类型的 Variant。 CInt(expression) expression 参数是任意有效的表达式。 说明 通常,可
Chr 函数 返回与指定的 ANSI 字符代码相对应的字符。 Chr(charcode) charcode 参数是可以标识字符的数字。 说明 从 0 到 31 的数字表示标准的不可打印的
CDbl 函数 返回表达式,此表达式已被转换为 Double 子类型的 Variant。 CDbl(expression) expression 参数是任意有效的表达式。 说明 通常,您可
CDate 函数 返回表达式,此表达式已被转换为 Date 子类型的 Variant。 CDate(date) date 参数是任意有效的日期表达式。 说明 IsDate 函数用于判断 d
CCur 函数 返回表达式,此表达式已被转换为 Currency 子类型的 Variant。 CCur(expression) expression 参数是任意有效的表达式。 说明 通常,
CByte 函数 返回表达式,此表达式已被转换为 Byte 子类型的 Variant。 CByte(expression) expression 参数是任意有效的表达式。 说明 通常,可以
CBool 函数 返回表达式,此表达式已转换为 Boolean 子类型的 Variant。 CBool(expression) expression 是任意有效的表达式。 说明 如果 ex
Atn 函数 返回数值的反正切值。 Atn(number) number 参数可以是任意有效的数值表达式。 说明 Atn 函数计算直角三角形两个边的比值 (number) 并返回对应角的弧
Asc 函数 返回与字符串的第一个字母对应的 ANSI 字符代码。 Asc(string) string 参数是任意有效的字符串表达式。如果 string 参数未包含字符,则将发生运行时错误。
Array 函数 返回包含数组的 Variant。 Array(arglist) arglist 参数是赋给包含在 Variant 中的数组元素的值的列表(用逗号分隔)。如果没有指定此参数,则
Abs 函数 返回数字的绝对值。 Abs(number) number 参数可以是任意有效的数值表达式。如果 number 包含 Null,则返回 Null;如果是未初始化变量,则返回 0。
FormatPercent 函数 返回表达式,此表达式已被格式化为尾随有 % 符号的百分比(乘以 100 )。 FormatPercent(expression[,NumDigitsAfterD
FormatNumber 函数 返回表达式,此表达式已被格式化为数值。 FormatNumber( expression [,NumDigitsAfterDecimal [,Inc
我是一名优秀的程序员,十分优秀!