gpt4 book ai didi

c# - 从 Expression> 创建 setter Expression>

转载 作者:行者123 更新时间:2023-11-30 20:31:19 24 4
gpt4 key购买 nike

我有一个 Expression<Func<IMyclass, int>>我想将其转换为类型为 Expression<Action<object, object>> 的 setter .如何实现?

问题是 object范围。使用正确的类型 ( string) 这会很容易。

class Foo
{
public Bar Bar { get; set; }
}
class Bar
{
public string Baz { get; set; }
}

static void Main(string[] args)
{
var expr = GetExpression(t => t.Bar.Baz);
var member = expr.Body as MemberExpression;

var p = Expression.Parameter(typeof(object), "p");
// This does not work...
var assign = Expression.Assign(member, p);
var lambda = Expression.Lambda<Action<object, object>>(assign, p);

object o = new Foo();
object v = "test";
lambda.Compile().Invoke(o, v);
}

private static Expression<Func<Foo, string>> GetExpression(Expression<Func<Foo, string>> expr)
{
return expr;
}

最佳答案

这是可能的,但并非微不足道。首先,您需要重写您的原始表达式。现在它有这种形式:

(Foo t) => t.Bar.Baz;

你需要它是这样的:

(object t) => ((Foo)t).Bar.Baz;

所以你需要表达式访问者:

private class ReplaceParameterExpressionVisitor : System.Linq.Expressions.ExpressionVisitor {
private readonly ParameterExpression _toReplace;
private readonly ParameterExpression _replaceWith;
public ReplaceParameterExpressionVisitor(ParameterExpression toReplace, ParameterExpression replaceWith) {
_toReplace = toReplace;
_replaceWith = replaceWith;
}

protected override Expression VisitParameter(ParameterExpression node) {
if (node == _toReplace)
// replace with new parameter and convert to the old parameter type
return Expression.Convert(_replaceWith, _toReplace.Type);
return base.VisitParameter(node);
}
}

然后你的代码变成:

static void Main(string[] args)
{
var expr = GetExpression(t => t.Bar.Baz);
var member = expr.Body as MemberExpression;

// define new parameter of type object
var target = Expression.Parameter(typeof(object), "t");
var value = Expression.Parameter(typeof(object), "p");
// replace old parameter of type Foo to new one
member = (MemberExpression) new ReplaceParameterExpressionVisitor(expr.Parameters[0], target).Visit(member);
// convert value to target type, because you cannot assign object to string
var assign = Expression.Assign(member, Expression.Convert(value, member.Type));
// now we have (target, value) => ((Foo)target).Bar.Baz = (string) value;
var lambda = Expression.Lambda<Action<object, object>>(assign, target, value);

var o = new Foo();
// set bar or will throw null reference
o.Bar = new Bar();
object v = "test";
lambda.Compile().Invoke(o, v);
}

关于c# - 从 Expression<Func<IMyclass, int>> 创建 setter Expression<Action<object, object>>,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43409713/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com