c - 如何获得正确的时间

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#include <stdio.h>
// this creates the structure  
struct time
{
    int hour;
    int minute;
    int second;
};

//function that calculates the time

struct time timeUpdate(struct time now)
{

    now.second = now.second + 1;

    if (now.second == 60)
    {
        now.second = 0;
        now.minute = now.minute + 1;

        if (now.minute == 60)
        {
            now.minute = 0;
            now.hour = now.hour + 1;
        }
            if (now.hour = 60)
            {
                now.hour = 0;
            }
    }
    return now;
}

//user input and output   
int main(void)
{
    struct time currentTime, nextTime;

    printf("Please enter the current time: ");
    scanf("%i:%i:%i\n", &currentTime.hour, &currentTime.minute, &currentTime.second);

    nextTime = timeUpdate(currentTime);

    printf("%.2i:%.2i:%.2i\n", nextTime.hour, nextTime.minute, nextTime.second);

    return 0;
}

Answer 1

假设您的输入有效(0 <= 小时 <= 23 && 0 <= 分钟 <= 59 && 0 <= 秒 <= 59)，以下是我的观察结果:

• 在 timeUpdate 中你说 now.hour = 60。你必须检查 now.hour 是否等于 24(if (now.hour == 24))你的函数应该是这样的:

  now.second = now.second + 1;
  
  if (now.second == 60)
  {
      now.second = 0;
      now.minute = now.minute + 1;
  
      if (now.minute == 60)
      {
          now.minute = 0;
          now.hour = now.hour + 1;
  
          if (now.hour == 24)
          {
              now.hour = 0;
          }
      }
  }
  
  return now;
  

• 我从 scanf 中删除了 '\n'，因为我很困惑为什么程序不显示结果(我必须写一个字符并按 Enter 键才能看到结果)。现在该行看起来像这样 scanf("%i:%i:%i", &currentTime.hour, &currentTime.minute, &currentTime.second);