c - 无论如何，是否可以创建一个 if 语句来打印输出，说明我已经超出了多少公斤？

Question

另外，公斤可以准确地测量到 0.5 公斤吗？例如，物体的最大重量为 20 公斤，但我输入的物体重量为 22.5 公斤。因此输出将是“您已超出 2.5 公斤”。反之亦然(输入=15公斤，输出=您尚未达到最小重量。您还缺少x公斤)。而且距离也可以吗？例如，最小距离为 10 公里，最大距离为 2000 公里，但我输入 x 公里，它要么小于 10 公里，要么大于 2000 公里。输出将是“您的距离减少/增加了 y 公里。”

<小时/>

#include <stdio.h>   //standard i/o
#include <math.h>   //roundoff

//Do not accept package’s weight less than 2 kg or more than 20 kg. And do not accept
//distance less than 10 km or more than 2000 km. These are the company’s policies.

int main()
{
    float weight, charges, rate;
    int distance;

    printf("Enter weight in kg: ");
    scanf_s("%f", &weight);

    printf("Shipping in distance in km: ");
    scanf_s("%d", &distance);

    if (weight < 2 || weight > 20 || distance < 10 || distance > 2000)
    {
        printf("The minimum weight is 2kg and the maximum weight is 20kg.\nThe minimum distance is 10km and the maximum distance is 2000km.");
        return 0;
    }
    else if (weight < 6)
    {
        rate = 2.2;
    }
    else if (weight < 10)
    {
        rate = 3.7;
    }
    else
    {
        rate = 4.8;
    }

    charges = (weight * rate);
    printf("Charges for %f", weight);
    printf(" kg and shipping distance of %d", distance);
    printf(" km are : RM%f", charges);
    return 0;
}

Answer 1

其实很简单。分别使用 if 语句来增加或减少重量或距离。即

#include<stdio.h> 

int main() 
{ 
    int distance;
    float weight;
    printf("Enter weight in kg:\n");
    scanf("%f",&weight);
    printf("Shipping in distance in km:\n");
    scanf("%d",&distance);
    if(weight>=20)
    {
        printf("you have exceeded by %f kg\n",weight-20);
    }
    else if(weight<=2)
    {
        printf("You have not achieved the minimum weight. You are short of %f kg\n",2-weight);    
    }
    if(distance>=2000)
    {
        printf("Your distance is more by %d km\n",distance-2000);
    }
    else if(distance<=10)
    {
        printf("Your distance is less by %d km\n",10-distance);
    }
}