javascript - 通过删除不需要的嵌套对象属性来过滤对象数组

Question

我有一个包含工作日对象的数组，我想按“打开”或“关闭”中包含 null 的元素过滤这些对象(不希望它们存在于我的最终数组中)。

let array = [
             [
               {"weekday":1,"opens":"09:00","closes":"11:00"}, 
               {"weekday":1,"opens":null,"closes":null}
             ],
             [
               {"weekday":2,"opens":"09:00","closes":"11:00"}, 
               {"weekday":2,"opens":"12:30","closes":"17:00"},
               {"weekday":2,"opens":"18:00","closes":"null"}
             ], ...
           ]

我想返回一个新创建的数组，这样我就不会改变原始数组。

我目前的解决方案看起来像那样但感觉很丑

let newArray = [];

array.forEach( (day, index)  => {
    day = day.filter( timeblock => 
       timeblock.opens != null && timeblock.closes != null
    );
    newArray.push(day);
});

如何更优雅地过滤嵌套数组？ (如果需要，jsfiddle:https://jsfiddle.net/2jukvsoy/1/)

Answer 1

let newArray = array.map(day => 
    day.filter(timeblock => 
        timeblock.opens != null && timeblock.closes != null
    )
);