c - 字符串中的单词排序

Question

我正在尝试创建一个函数，从用户那里获取一个字符串和一个数字，然后使每个单词的长度与我从用户那里获得的数字相同并打印新字符串。
例如:

abcd__efgh_i
number = 3
and i should get
abc_def_ghi

#include < stdio.h > 
void f(char * p, int n) {
    int i = 0, br = 0, d, m = 0, br1 = 0, g;
    while (p[i] != '\0') {
        if (p[i] != '\0') {
            br++;
        }
        i++;
    }
    if (br % n == 0) {
        d = (br / n) - 1;
    } else {
        d = (br / n);
    }
    g = br + d;
    char b[g];
    i = 0;
    while (p[i] == '\0') {
        if (p[i] == '\0') {
            while (p[i] == '\0') {
                i++;
            }
        } else {
            b[m] = '\0';
            m++;
            br1 = 0;
        }
        b[m] = p[i];
        m++;
        i++;
        br1++;
        if (m == g) {
            b[m] = '\0';
        }
    }

    printf("%s", b);
}

Answer 1

#include <stdio.h>

void
shuffle (const char *str, unsigned int n) {
    unsigned int i = 0;

    // loop until the end of the string is found
    while (*str) {

        // Examine the current character. If it is not a space, output it
        // and increment the number of characters output so far in the current word
        if (*str != ' ') {
            putchar (*str);
            ++i;
        }

        // Move to the next character 
        ++str;

        // Check if we have output "n" characters so far. If so, output a space to 
        // separate words and reset the character count
        if (i == n) {
            putchar (' ');
            i = 0;
        }
    }
    // Put a single new line at the end
    putchar ('\n');
}

int
main () {
    shuffle ("abcd  efgh   i jk", 3);
}