c++ - 我无法标记我的角色，我该如何到达那里？

Question

using namespace std;

char *fx[65537];

void main()
{

    FILE *fp;
    int i = 0;
    int c = 0;
    char *token = NULL;
    char str1[] = " ";

    fp = fopen("fx.txt", "r");
    char s[51];
    for (c = 0; i <= 65536; c++) 
    {
        token = strtok(fx[c], str1);
        while (token != NULL) 
        {
            printf("token : %s", token);
            putchar('\n');
            token = strtok(NULL, str1);
        }
    }

    while (!feof(fp))
    {
        i = i++;
        fgets(s, 50, fp);
        fx[i] = s;  //fx 포인터에 s의 임시배열 저장
    }

    fclose(fp);
}

你好我想制作一个程序，用一行读取 *.txt 文件并保存字符指针我标记这个字符并保存例如

有txt测试.txt

123 654 8765 4213
321 565 4687 8765
652 126 6874 3215

那么，

char *a[3] = {123 654 8765 4213, 321 565 4687 8765, 652 126 6874 3215};
char b[3][4];
char b[0][] = {123, 654, 8765, 4213};
char b[1][] = {321, 565, 4687, 8765};
char b[2][] = {652, 126, 6874, 3215};

但我不知道该怎么做:(

你能帮我吗？

Answer 1

使用 vector 和字符串

#include <iostream>
#include <fstream>
#include <vector>
#include <iterator>
#include <string>

int main() {
  std::ifstream input("fx.txt");
  std::vector<std::string> v((std::istream_iterator<std::string>(input)),std::istream_iterator<std::string>());

  for ( std::vector<std::string>::const_iterator iter = v.begin();iter != v.end(); ++iter ) {
    std::cout << *iter << std::endl;//print by iterator
  }
  for(int i=0;i<v.size();++i)
    std::cout << v[i] << std::endl;//print by []
}

<小时/>

作者:C

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char *fx[65537];

int main(){
    FILE *fp;
    int i = 0, j;
    int c = 0;
    char *token = NULL;
    char str1[] = " \n";
    char s[51];

    fp = fopen("fx.txt", "r");
    while (fgets(s, sizeof(s), fp)){
        token = strtok(s, str1);
        while (token != NULL) {
            fx[i++] = strdup(token);
            if(i == 65537)
                break;
            token = strtok(NULL, str1);
        }
    }
    fclose(fp);

    c = i;
    for(i=0;i<c;++i)
        printf("%s ", fx[i]);
    printf("\n\n");

    char *(*b)[4] = (char *(*)[4])fx;
    for(i=0;i<3;++i){
        for(j=0;j<4;++j)
            printf("%s ", b[i][j]);
        printf("\n");
    }
    //deallocation
    for(i=0;i<c;++i)
        free(fx[i]);
    return 0;
}