c - C语言中如何将缓冲区复制到字符指针

Question

所以我有一个固定大小的字符数组:

char buff[100];

我有一个字符指针:

char *ptr;

现在，缓冲区将被部分或全部填充。我想将缓冲区的内容复制到 ptr。我该怎么做？

谢谢

更新:

int rcd; // Received bytes
int temp = 0; // This is used as a size to realloc the dataReceived character pointer
int packetLength = 0; // This is the total packet length
int *client = (int*) data;
int cli = *client; // The client socket descriptor
char buff[100]; // Buffer holding received data
char *dataReceived = malloc(0);

while ((rcd = recv(cli, buff, 100, MSG_DONTWAIT)) > 0) 
{
    dataReceived = realloc(dataReceived, rcd + temp + 1); // Realloc to fit the size of received data
    strcat(dataReceived, buff); // Concat the received buffer to dataReceived
    temp = rcd;
    packetLength = packetLength + rcd;
    memset(buff, 0, 100); // Reinitialize the buffer for the next iteration
}

Answer 1

要将 buffer 的内容复制到 ptr 指向的位置，请使用:

memcpy(ptr, buffer, sizeof(buffer));

memcpy 的第一个参数是目标，第二个是源(与 strcpy 和 strcat 的顺序相同)，第三个是要复制的字节数。