函数的代码解释

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我得到了一个代码，我需要对其进行解释。不幸的是我不明白该程序的几行，并且我发现很难解释它。如果有人可以帮助我更好地解释代码并解释我的解释中未包含的部分，我将不胜感激。这些是我发现很难解释的程序部分:

 return (array[n] + total(array,n-1));

和

(array[n] == 1) ?

这是我解释代码的尝试:

A function named total is defined before the main function containing an array of 14 objects and an integer n as it’s parameters. The code in the function includes an if loop, if n is equal to 0, array will return 0 objects. Otherwise return array of n objects added with the total. In the main function, an array containing 14 objects is defined. Sum, n and cattotal are all defined as integers. The sum is set to the total. A for loop is used to get the information from the array and print how many cats there are per bus stop. Recursion is used for the loop to keep repeating until the array is run out of objects, that is 14 objects. The bus stop total is printed all along the way until it reaches the final stop. At the end, the total amount of cats seen is also printed.

代码:

#include <stdio.h>

int total(int array[14], int n)
{

    if (n == 0) {
        return array[0];
    }

    return (array[n] + total(array,n-1));
}

int main(void)
{
    int array[14] = {5,1,3,2,3,7,0,1,0,1,4,0,2,1}; //array storing 14 objects
    int sum, n;
    int cattotal = 0;

    sum = total(array,13);

    for (n=0; n < 14; n++){

    (array[n] == 1) ?

    printf("Bus stop #%d : %d cat\n",(n+1),array[n]):

    printf("Bus stop #%d : %d cats\n",(n+1),array[n]);

    cattotal += array[n];

    printf("Bus stop#%d total: %d cats\n\n)",(n+1),cattotal);
    }

    printf("\nTotal amount of cats seen: %d\n",sum);

    return 0;
}

Answer 1

int Total(int array[14], int n) 是一个递归函数，生成直到索引 n 为止的所有元素的总和。

(array[n] == 1) ?
printf("Bus stop #%d : %d cat\n",(n+1),array[n]):
printf("Bus stop #%d : %d cats\n",(n+1),array[n]);

意思相同

if (array[n] == 1) {
    printf("Bus stop #%d : %d cat\n",(n+1),array[n]);
} else {
    printf("Bus stop #%d : %d cats\n",(n+1),array[n]);
}

用三元运算符表示？ :