C – 初始化包含多个数组的二维全局静态结构数组

Question

我想初始化一个二维全局静态结构数组，其中包含数组。以下似乎不起作用。

struct MyStuct{
    int a;
    int b;
    int c[2];
    int d[2];
};
STATIC MyStuct[2][3] = {
{{1,1,{1,1},{1,1}},
{2,2,{2,2},{2,2}},
{3,3,{3,3},{3,3}}},
{{7,7,{7,7},{7,7}},
{8,8,{8,8},{8,8}},
{9,9,{9,9},{9,9}}}
};

有什么建议吗？

谢谢

Answer 1

struct MyStuct{
    int a;
    int b;
    int c[2];
    int d[2];
};

static struct MyStuct test [2][3] =
{
//            |     COL 0     |  |     COL 1     |  |    COL 2      |
/* ROW 0 */ { {1,1,{1,1},{1,1}}, {2,2,{2,2},{2,2}}, {3,3,{3,3},{3,3}} },
/* ROW 1 */ { {7,7,{7,7},{7,7}}, {8,8,{8,8},{8,8}}, {9,9,{9,9},{9,9}} }
};

您的矩阵声明必须使用结构作为类型，即struct MyStuct test

仅供测试:

#include <stdio.h>

int main (void)
{
    struct MyStuct{
        int a;
        int b;
        int c[2];
        int d[2];
    };

    struct MyStuct test [2][3] =
    {
    //            |     COL 0      |       COL 1       |      COL 2        |
    /* ROW 0 */ { {1,1,{1,1},{1,1}}, {2,2,{2,2},{2,2}}, {3,3,{3,3},{3,3}} },
    /* ROW 1 */ { {7,7,{7,7},{7,7}}, {8,8,{8,8},{8,8}}, {9,9,{9,9},{9,9}} }
    };

    for (size_t i=0; i< 2; i++)
    {
        for (size_t j=0; j<3; j++)
        {
            printf("test[%zu][%zu].a = %d\n", i, j, test[i][j].a);
            printf("test[%zu][%zu].b = %d\n", i, j, test[i][j].b);

            for (size_t z=0; z<sizeof(test[i][j].c)/sizeof(test[i][j].c[0]); z++)
            {
                printf("test[%zu][%zu].c[%zu] = %d\n", i, j, z, test[i][j].c[z]);
            }

            for (size_t z=0; z<sizeof(test[i][j].c)/sizeof(test[i][j].c[0]); z++)
            {
                printf("test[%zu][%zu].d[%zu] = %d\n", i, j, z, test[i][j].c[z]);
            }

            printf("\n");
        }
    }

    return 0;
}