c# - 从名称为 ID 的 json 对象创建一个强类型的 c# 对象

Question

我正在尝试使用知名在线 session 提供商的 API。他们的 API 调用之一返回如下所示的对象。

{
    "5234592":{
    "pollsAndSurveys":{
        "questionsAsked":1,
        "surveyCount":0,
        "percentageSurveysCompleted":0,
        "percentagePollsCompleted":100,
        "pollCount":2},
    "attendance":{
        "averageAttendanceTimeSeconds":253,
        "averageInterestRating":0,
        "averageAttentiveness":0,
        "registrantCount":1,
        "percentageAttendance":100}
    },
    "5235291":{
    "pollsAndSurveys":{
        "questionsAsked":2,
        "surveyCount":0,
        "percentageSurveysCompleted":0,
        "percentagePollsCompleted":0,
        "pollCount":0},
    "attendance":{
        "averageAttendanceTimeSeconds":83,
        "averageInterestRating":0,
        "averageAttentiveness":0,
        "registrantCount":1,
        "percentageAttendance":100}
    }
}

我正在尝试在 C# 中创建一个强类型对象，以便我可以处理这些数据。我可以为 pollsAndSurveys 位和出勤位创建对象，但我不知道如何处理 ID 号，在本例中为 5234592 和 5235291，这是 session 的标识符。

public class AttendanceStatistics
{
    [JsonProperty(PropertyName = "registrantCount")]
    public int RegistrantCount { get; set; }

    [JsonProperty(PropertyName = "percentageAttendance")]
    public float PercentageAttendance{ get; set; }

    [JsonProperty(PropertyName = "averageInterestRating")]
    public float AverageInterestRating { get; set; }

    [JsonProperty(PropertyName = "averageAttentiveness")]
    public float AverageAttentiveness { get; set; }

    [JsonProperty(PropertyName = "averageAttendanceTimeSeconds")]
    public float AverageAttendanceTimeSeconds { get; set; }
}

public class PollsAndSurveysStatistics
{
    [JsonProperty(PropertyName = "pollCount")]
    public int PollCount { get; set; }

    [JsonProperty(PropertyName = "surveyCount")]
    public float SurveyCount { get; set; }

    [JsonProperty(PropertyName = "questionsAsked")]
    public int QuestionsAsked { get; set; }

    [JsonProperty(PropertyName = "percentagePollsCompleted")]
    public float PercentagePollsCompleted { get; set; }

    [JsonProperty(PropertyName = "percentageSurveysCompleted")]
    public float PercentageSurveysCompleted { get; set; }
}

public class SessionPerformanceStats
{
    [JsonProperty(PropertyName = "attendance")]
    public AttendanceStatistics Attendance { get; set; }

    [JsonProperty(PropertyName = "pollsAndSurveys")]
    public PollsAndSurveysStatistics PollsAndSurveys { get; set; }
}

public class WebinarPerformanceStats
{
    public List<SessionPerformanceStats> Stats { get; set; }
}

我很确定 WebinarPerformanceStats 是问题所在，但我不知道从这里去哪里。我必须改变什么才能得到

NewtonSoft.Json.JsonConvert.DeserializeObject<WebinarPerformanceStats>(theJsonResponse)

上类？

Answer 1

让你的根对象成为一个字典:

var dictionary = JsonConvert.DeserializeObject<Dictionary<string, SessionPerformanceStats>>(theJsonResponse);

Json.NET 将字典从 JSON 对象序列化到 JSON 对象，并将键转换为属性名称。在您的情况下，ID 号将被反序列化为字典键。如果您确定它们始终是数字，则可以这样声明它们:

var dictionary = JsonConvert.DeserializeObject<Dictionary<long, SessionPerformanceStats>>(theJsonResponse);

参见 Serialize a Dictionary和 Deserialize a Dictionary