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c# - 创建一个唯一的 5 个字符的字母数字字符串

转载 作者:行者123 更新时间:2023-11-30 20:20:28 25 4
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我们正在考虑创建促销代码以发送给客户,我们被告知发送的每个代码必须是唯一的 - 5 个字符 - 字母数字。

我想过对连接的字符串进行哈希处理并获取哈希的前 5 个字符,但很有可能会一次又一次地出现相同的 5 个字符。

任何人都可以给我任何关于创建这个每次都是唯一的 5 字符字母数字字符串的指示吗?

最佳答案

正如我在其他回答的评论中提到的,它可能不足以满足您的目的。我编写了更多代码来生成一串随机字母数字字符。这一次,它们不限于 0-9 和 A-F——即随机生成的十六进制等价物 nibbles .相反,它们由全范围的字母数字字符组成,至少是大写字母。考虑到我们从 16 个可能的十六进制字符到 36 个可能的完整字母表和 0-9 字符,这应该足以增加唯一性的可能性。

尽管如此,当我尝试运行它超过 10,000,000 次时,仍然有很多重复项。这只是野兽的本性:你用这么短的字符串被骗的可能性相当高。无论如何,它就在这里。你可以玩弄它。如果您的客户不介意小写字母——例如如果“RORYAP”不同于“RoryAp”——那么这甚至会进一步增加唯一性的可能性。

/// <summary>
/// Instances of this class are used to geneate alpha-numeric strings.
/// </summary>
public sealed class AlphaNumericStringGenerator
{
/// <summary>
/// The synchronization lock.
/// </summary>
private object _lock = new object();

/// <summary>
/// The cryptographically-strong random number generator.
/// </summary>
private RNGCryptoServiceProvider _crypto = new RNGCryptoServiceProvider();

/// <summary>
/// Construct a new instance of this class.
/// </summary>
public AlphaNumericStringGenerator()
{
//Nothing to do here.
}

/// <summary>
/// Return a string of the provided length comprised of only uppercase alpha-numeric characters each of which are
/// selected randomly.
/// </summary>
/// <param name="ofLength">The length of the string which will be returned.</param>
/// <returns>Return a string of the provided length comprised of only uppercase alpha-numeric characters each of which are
/// selected randomly.</returns>
public string GetRandomUppercaseAlphaNumericValue(int ofLength)
{
lock (_lock)
{
var builder = new StringBuilder();

for (int i = 1; i <= ofLength; i++)
{
builder.Append(GetRandomUppercaseAphanumericCharacter());
}

return builder.ToString();
}
}

/// <summary>
/// Return a randomly-generated uppercase alpha-numeric character (A-Z or 0-9).
/// </summary>
/// <returns>Return a randomly-generated uppercase alpha-numeric character (A-Z or 0-9).</returns>
private char GetRandomUppercaseAphanumericCharacter()
{
var possibleAlphaNumericValues =
new char[]{'A','B','C','D','E','F','G','H','I','J','K','L',
'M','N','O','P','Q','R','S','T','U','V','W','X','Y',
'Z','0','1','2','3','4','5','6','7','8','9'};

return possibleAlphaNumericValues[GetRandomInteger(0, possibleAlphaNumericValues.Length - 1)];
}

/// <summary>
/// Return a random integer between a lower bound and an upper bound.
/// </summary>
/// <param name="lowerBound">The lower-bound of the random integer that will be returned.</param>
/// <param name="upperBound">The upper-bound of the random integer that will be returned.</param>
/// <returns> Return a random integer between a lower bound and an upper bound.</returns>
private int GetRandomInteger(int lowerBound, int upperBound)
{
uint scale = uint.MaxValue;

// we never want the value to exceed the maximum for a uint,
// so loop this until something less than max is found.
while (scale == uint.MaxValue)
{
byte[] fourBytes = new byte[4];
_crypto.GetBytes(fourBytes); // Get four random bytes.
scale = BitConverter.ToUInt32(fourBytes, 0); // Convert that into an uint.
}

var scaledPercentageOfMax = (scale / (double) uint.MaxValue); // get a value which is the percentage value where scale lies between a uint's min (0) and max value.
var range = upperBound - lowerBound;
var scaledRange = range * scaledPercentageOfMax; // scale the range based on the percentage value
return (int) (lowerBound + scaledRange);
}
}

关于c# - 创建一个唯一的 5 个字符的字母数字字符串,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36625891/

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