c - 将新字符串值分配给 char 数组时出错

Question

这个问题已经有答案了:

"error: assignment to expression with array type error" when I assign a struct field (C) (5 个回答)

已关闭 4 年前。

当尝试将新的字符串值分配给 c 中现有的 char 数组时，出现以下错误:

assignment to expression with array type
  employees[id].FirstMiddleName = NewFirstMiddleName;
                            ^                        

我认为这两个变量都是相同大小的数组，所以我不明白错误指的是什么或如何修复它。

struct employee {
    char LastName[30];
    char FirstMiddleName[35];
    float Salary;
    int YearHired;
};

int modify(int id) {
    char NewLastName[30];
    char NewFirstMiddleName[35];
    float NewSalary;
    int NewYearHired;

    printf("Enter new first (and middle) name(s): \n");
    gets(NewFirstMiddleName);
    employees[id].FirstMiddleName = NewFirstMiddleName;

    printf("Enter new last name: \n");
    gets(NewLastName);
    employees[id].LastName = NewLastName;
    ....

}

int main() {

    struct employee *ptr, person;
    ptr = &person;

    ptr->LastName[0] = '\0';
    ptr->FirstMiddleName[0] = '\0';
    ptr->Salary = -1;
    ptr->YearHired = -1;

    for(int i = 0; i < 20; i++) {
            employees[i] = person;
            //printf("%i\n", i);
    }
    ....
}

Answer 1

employees[id].FirstMiddleName 是数组类型，不能使用 =

赋值

assignment operator shall have a modifiable lvalue as its left operand. A modifiable lvalue is an lvalue that does not have array type

在这种情况下，您需要使用strcpy

strcpy(employees[id].FirstMiddleName, NewFirstMiddleName);