c - 斐波那契数列存在一些运行时错误

Question

[在此处输入图像描述][1][此处当我在 if(series==1) return 之前在斐波那契定义函数中采用 if(series==0) return 0; 时1; 然后斐波那契数列打印成功，但是当我删除这一行然后编译我的程序时，它需要 term inout 然后显示一条错误消息，如

Fibonacci.exe has stop working but when I add that line program executing successfully. what happening that. somebody will tell me ][2] here's my code :

    #include<stdio.h>
int fibonacci(int);  // declaration of fibonacci function.

int main(){
    int input_num,i,series=1;
    printf("Enter the term you want to print fibonacci series : ");
    scanf("%d", &input_num);

    printf("\n Fibonacci Series Are : ");

    for(i=0; i<input_num; i++){
        printf("%d,", fibonacci(series));
        series++;
    }

    return 0;
}

//defination of fibonacci function
int fibonacci(int series){


    if(series==1) return 1;

    return(fibonacci(series-1)+fibonacci(series-2));

}

Answer 1

if (series==1) return 1;

这存在一个问题，您还使用 series-2 调用该函数，因此它可能会小于 1。替换为:

if (series<=1) return 1;

另请参阅“防御性编程”