c - "Stray '\' in program, ' 否则 ' without ' 如果'

Question

我刚刚学习 C，我正在做一个练习，其中我必须打印 1-99.99 范围内的 10 x 4 数字表，仅打印大于 67 的数字，然后打印每行的平均值。但是我的代码无法编译，我不知道为什么。这就是我所拥有的

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define N 100
int main(void)
{
    int r; 
    int c;
    double num;
    double sum;
    int count;
    double avg;
    for(c = 0; c < 10; c++)
        {
            avg = 0;
            sum = 0;
            count = 0;
            for(r = 1; r< 5; r++)
                {
                    num = (float) N * rand() / (RAND_MAX + 1.0);
                if (num > 67.0) 
                    count = count + 1;
                    sum = sum + num;
                    printf("%.2f, " num);
                else 
                    printf("%4s");

               }
        if(count = 0)
        continue;
        avg = (sum\count);
        printf("%.2f |", avg);
        printf("\n\n");
      }


}

我收到以下错误

line 24 expected '<' before num 
line 25 else without a previous if statement 
line 31 stray '\' in program 
line 31 expected'>' before count

我查看了它们，但我无法弄清楚它们？

Answer 1

您需要替换avg = (sum/count);。您还应该更改为 if(count == 0)。而且您缺少一些花括号。

建议的更改:

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define N 100

int main(void)
{
    int r; 
    int c;
    double num;
    double sum;
    int count;
    double avg;
    for(c = 0; c < 10; c++)  {
       avg = 0;
       sum = 0;
       count = 0;
       for(r = 1; r< 5; r++)  {
           num = (float) N * rand() / (RAND_MAX + 1.0);
           if (num > 67.0) {
             count = count + 1;
             sum = sum + num;
             printf("%.2f, ", num);
           }
           else 
             printf("%4s");

        }
        if(count = 0)
           continue;
        avg = (sum/count);
        printf("%.2f |\n\n", avg);
      }

}