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c - 使用 fgets() 后查找字符串长度

转载 作者:行者123 更新时间:2023-11-30 20:05:51 25 4
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我试图找到字符串1(s1)的长度..但它给出的值是0,并且输入s1 =“HELLO”,因为这个错误无法执行我所在的for循环使用字符串1的长度。

以下是代码...在 gcc 版本 4.9.1(Ubuntu 4.9.1-16ubuntu6)中工作正常,但在在线编译器(gcc 4.9.2,C99 标准)中工作正常

/*To check if common characters are present in two strings*/
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <stdio_ext.h>
#define SIZE 100
int main() {
int m, i, j, t, len1;
char *s1, *s2;
scanf("%d", &t); //No. test cases
__fpurge(stdin);

for(m = 0; m < t; m++)
{
int res = 0;

s1 = (char *)malloc( SIZE * sizeof( char ));
s2 = (char *)malloc( SIZE * sizeof( char ));

fgets(s1, SIZE, stdin);
fgets(s2, SIZE, stdin);

*(s1 + strlen(s1) - 1) = '\0';
*(s2 + strlen(s2) - 1) = '\0';

len1 = strlen(s1); // len1 is storing as 0
printf("%d", len1 );
for (i = 0; i < strlen(s1); i++)
{
for (j = 0;j < strlen(s2); j++)
{
if ( *(s1 + i) == *(s2 + j) )
res = 1;
}
}

if(res == 1)
printf( "YES\n" );
else
printf("NO\n");
}
return 0;
}

最佳答案

有一种相当标准的方法来处理使用 fgetsgetline 从文件读取后从输入中剥离换行符。有一些变体,但都用空终止字符替换换行符。这是使用您的代码的示例:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define SIZE 64

int main (void) {

char *s1 = NULL;
char *s2 = NULL;
size_t len1 = 0;
size_t len2 = 0;

s1 = malloc (SIZE * sizeof *s1);
s2 = malloc (SIZE * sizeof *s2);

printf ("\n Enter s1: ");
fgets (s1, SIZE, stdin);
printf ("\n Enter s2: ");
fgets (s2, SIZE, stdin);

/* strip newline or carriage rtn */
len1 = strlen (s1);
while (len1 > 0 && (s1[len1-1] == '\n' || s1[len1-1] == '\r'))
s1[--len1] = 0;

len2 = strlen (s2);
while (len2 > 0 && (s2[len2-1] == '\n' || s2[len2-1] == '\r'))
s2[--len2] = 0;

printf ("\n len1 : %zu s1 : %s\n len2 : %zu s2 : %s\n\n", len1, s1, len2, s2);

if (s1) free (s1);
if (s2) free (s2);

return 0;
}

输出

$ ./bin/fgets_strip

Enter s1: This is s1

Enter s2: This is s2

len1 : 10 s1 : This is s1
len2 : 10 s2 : This is s2

关于c - 使用 fgets() 后查找字符串长度,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29305821/

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