javascript - 使用 node js 动态构建 JSON

Question

我在特定文件夹中有 (n) 个 JSON 文件:

为简单起见，假设有 3 个 JSON 文件 Animal.json、Noun.json、POS.JSON

它们的内容分别是

Animal.json

[
  {
    "label": "Dinosaur",
    "sample": ["#Noun Rex","saurus"]
  },
  {
    "label": "Lion",
    "sample": ["simba"]
  },
  {
    "label": "Tiger",
    "sample": ["big cat"]
  }
]

Noun.json

[
      {
        "label": "Animal",
        "sample": ["Herbivore","Carnivore"]
      }
]

POS.json

[
          {
            "label": "Noun",
            "sample": ["Proper","Common"]
          }
    ]

我希望能够遍历特定文件夹中的所有 JSON 文件并动态构建以下格式的 JSON

label: {
      Dinosaur: {
        isA: 'Animal'
      },
      Lion: {
        isA: 'Animal'
      },
      Tiger: {
        isA: 'Animal'
      },
      Animal: {
        isA: 'Noun'
      },
      Noun: {
      isA: 'POS'
      }
    },
    sample: {
      '#Noun rex|saurus': 'Dinosaur',
      'simba': 'Lion'
      'big cat': 'Tiger',
      'Herbivore|Carnivore' : 'Animal',
      'Proper|Common' : 'Noun'

    }

到目前为止我的逻辑:

function buildJSON() {
  fs.readdirSync('/path/to/file').forEach(file => {

    const path = '/path/to/file' + file;
    const data = fs.readFileSync(path);
    const txt = JSON.parse(data);

    console.log(JSON.stringify(txt)); //Displays content of each file

   /* I need the logic to build the lable and sample for the output json */


  });
}

感谢任何帮助/指导。

Answer 1

您可以简单地使用 Array.reduce() 来创建一个 map :

let animal =  [ { "label": "Dinosaur", "sample": ["#Noun Rex","saurus"] }, { "label": "Lion", "sample": ["simba"] }, { "label": "Tiger", "sample": ["big cat"] } ];
let noun = [ { "label": "Animal", "sample": ["Herbivore","Carnivore"] } ];
let pos =[ { "label": "Noun", "sample": ["Proper","Common"] } ];
    
function getResult(arr, isA, result){
  result = arr.reduce((a, curr)=>{
    a.label = a.label || {};
    a.label[curr.label] = {
      "isA" : isA
    };
    a.sample = a.sample || {};
    a.sample[curr.sample.join("|")] = curr.label;
    return a;
  }, result);
  return result;
}
let result=  {};
getResult(animal, "Animal", result);
getResult(noun, "Noun", result);
getResult(pos, "Pos", result);
console.log(result);