c - 为什么子进程的最后一行不打印？

Question

#include <stdlib.h>
#include <sys/wait.h>
#include <unistd.h>
#include <stdio.h>


int main( ) {
    pid_t pid;
    int status = -1; 

    if ((pid = fork()) != 0) {
       printf("Father process wait child PID=%d\n", pid);
       wait(&status);
       printf("Child finish with status: %d\n",WEXITSTATUS(status));
       exit(0);
    }
    else {
       printf("Child process running...\n");
       execl("/bin/ls","ls", "-la", NULL);
       printf("Child ending...\n");
    }
}

编译此代码时，else 的最后一行不会打印，我不知道为什么。

Answer 1

http://linux.die.net/man/3/execl

The exec() family of functions replaces the current process image with a new process image. ....

Return Value

The exec() functions only return if an error has occurred. The return value is -1, and errno is set to indicate the error.