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c# - 从非静态类访问静态方法可能在 java 而不是在 c# 中

转载 作者:行者123 更新时间:2023-11-30 20:04:46 25 4
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从带有对象的非静态类访问静态方法。这在 C# 中是不可能的。由JAVA完成的地方。它是如何工作的?

java的例子

/**
* Access static member of the class through object.
*/
import java.io.*;

class StaticMemberClass {
// Declare a static method.
public static void staticDisplay() {
System.out.println("This is static method.");
}
// Declare a non static method.
public void nonStaticDisplay() {
System.out.println("This is non static method.");
}
}

class StaticAccessByObject {

public static void main(String[] args) throws IOException {
// call a static member only by class name.
StaticMemberClass.staticDisplay();
// Create object of StaticMemberClass class.
StaticMemberClass obj = new StaticMemberClass();
// call a static member only by object.
obj.staticDisplay();
// accessing non static method through object.
obj.nonStaticDisplay();
}
}

程序输出:

This is static method.
This is static method.
This is non static method.

如何在 C# 中执行此操作?提前致谢..

最佳答案

C# 禁止通过instance.Method 引用静态方法,只有Type.Method 是可以接受的。要调用静态方法,您需要遍历类型,而不是实例。
在您的情况下,这意味着 StaticMemberClass.staticDisplay() 有效,但 obj.staticDisplay() 无效。


When a method is referenced in a member-access (§7.6.4) of the form E.M, if M is a static method, E must denote a type containing M, and if M is an instance method, E must denote an instance of a type containing M.

(C# 语言规范版本 4.0 - 10.6.2 静态和实例方法)

When a static member M is referenced in a member-access (§7.6.4) of the form E.M, E must denote a type containing M. It is a compile-time error for E to denote an instance.

(C# 语言规范版本 4.0 - 10.3.7 静态和实例成员)

关于c# - 从非静态类访问静态方法可能在 java 而不是在 c# 中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12436148/

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