javascript - 如何从特定时间(例如上午 9 点到下午)以分钟为单位开始计时

Question

我想从上午 9 点到晚上 9 点以分钟为单位开始计时

Answer 1

回答标题中的问题:

您可以创建一个Date 并使用setHours、setMinutes 等将其时间设置为早上9 点。

然后您可以使用 - 找出两个日期之间的毫秒差值。除以 1000 * 60，您可以计算出以分钟为单位的差异。

const minutesSinceNineInTheMorning = (dateTime) => {
  const nineInTheMorning = new Date(dateTime);
  nineInTheMorning.setHours(9);
  nineInTheMorning.setMinutes(0);
  nineInTheMorning.setSeconds(0);
  nineInTheMorning.setMilliseconds(0);
  
  const msInAMinute = 1000 * 60;
  
  return (dateTime - nineInTheMorning) / msInAMinute;
};

console.log(minutesSinceNineInTheMorning(new Date()));

剩下的问题是找到 block 之间的重叠，既然您有常规数字可以使用，这应该是可行的。

如果您仍然需要解决最后一个问题的帮助，最好提出一个新问题或展示一些特定于所需逻辑的尝试。

附言这是我在午休时间写的一个简单示例，可能会帮助您入门:

const requestByJohn = { start: 220, end: 280, name: "John" };
const options = [
 {start: 225, end: 285, name: "Jane" },
 {start: 210, end: 270, name: "Aisha"},
 {start: 180, end: 240, name: "Brad" },
 {start: 180, end: 330, name: "Alice"},
 {start: 300, end: 360, name: "Yusef"},
 {start: 270, end: 330, name: "Rob"  }
];

const match = req => opt => ({
  // Calculate the overlap between two blocks
  overlap: opt.end <= req.start || opt.start > req.end
    ? 0
    : Math.min(req.end, opt.end) - Math.max(req.start, opt.start),
  // The earliest start time of this meeting
  start: Math.max(req.start, opt.start),
  label: `${req.name} - ${opt.name}`
});

const overlapRule = ({ overlap }) => overlap >= 30;
const sortLogic = (m1, m2) => 
  // Sort by overlap first
  m2.overlap > m1.overlap ?  1 : 
  m2.overlap < m1.overlap ? -1 :
  // Sort by start second
  m2.start > m1.start     ? -1 :
  m2.start < m1.start     ?  1 :
                             0 ;

// Chain match, filter, sort:
const bestMatches = options
  .map(match(requestByJohn))
  .filter(overlapRule)
  .sort(sortLogic);
  
console.log(
  "Best match:",
  bestMatches[0],
  "\nAll possibilities:",
  bestMatches
)

.as-console-wrapper { min-height: 100%; }