javascript - 创建具有所需树结构的对象

Question

我一直在尝试创建一个树结构:

var result = {
  email: {
    schema: {
      verified: 'email.verified',
      email_address: 'email.email_address',
      entity: {
        schema: {
          name: 'email.entity.name',
          type: 'email.entity.type',
          email: {
            schema: {
              verified: 'email.entity.email.verified',
              email_address: 'email.entity.email.email_address'
            }
          }
        }
      }
    }
  }
};

从下面给出的数组数据:

var schema = {
  'paths': [
    'email.email_address',
    'email.entity.email.email_address',
    'email.entity.email.verified',
    'email.entity.type',
    'email.entity.name',
    'email.verified',
    'created_at',
    'contact_numbers'
  ]
}

您看到我期望的输出具有嵌套在 n 级别中的 schema 属性，这是不可预测的。这取决于 paths 的值，例如 'email.entity.email.email_address'。您可以用点拆分它，看起来每个点都被输出中的 schema 属性替换。

我正在尝试使用递归，但我无法设置该流程。以下是我到目前为止尝试过的代码:

var schema = {
  'paths': [
    'email.email_address',
    'email.entity.email.email_address',
    'email.entity.email.verified',
    'email.entity.type',
    'email.entity.name',
    'email.verified',
    'created_at',
    'contact_numbers'
  ]
}
var newSchema = {};

var key = 'email';
var existKeys = schema.paths.filter((path) => path.includes(key + '.'));
var requiredObject = {};
existKeys.forEach((existKey) => {
  var splitKeys = existKey.split('.');
  splitKeys.forEach((splitKey, index) => {
    if (requiredObject[splitKey] && index + 1 === splitKeys.length) {
      requiredObject[splitKey].schema = existKey;
    } else {
      requiredObject[splitKey] = {
        'schema': {}
      }
    }
  });
});
console.log(requiredObject);

Answer 1

您可以减少路径并为每个找到的键取一个 schema 属性。

var schema = { paths: ['email.email_address', 'email.entity.email.email_address', 'email.entity.email.verified', 'email.entity.type', 'email.entity.name', 'email.verified', 'created_at', 'contact_numbers'] },
    result = schema.paths
        .filter(s => s.startsWith('email')) // or not or so, if so, maybe
        .reduce((r, p) => {
            var keys = p.split('.'),
                last = keys.pop();

            keys.reduce((o, k) => (o[k] = o[k] || { schema: {} }).schema, r)[last] = p;
            return r;
        }, {});

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }