gpt4 book ai didi

c - C 中的多线程

转载 作者:行者123 更新时间:2023-11-30 19:55:40 25 4
gpt4 key购买 nike

我是多线程新手,任何答案将不胜感激。我正在运行教程中的一个示例,该示例使用 3 个线程;两个由用户创建,一个用于 main 本身。代码如下:

#include <stdio.h>
#include <pthread.h>
#include <string.h>
#include <stdlib.h>

#define NUM_EMPLOYEES 2

/* global mutex for our program. assignment initializes it */
pthread_mutex_t a_mutex = PTHREAD_MUTEX_INITIALIZER;

struct employee {
int number;
int id;
char first_name[20];
char last_name[30];
char department[30];
int room_number;
};

/* global variable - our employees array, with 2 employees */
struct employee employees[] = {
{1, 12345678, "danny", "cohen", "Accounting", 101},
{2, 87654321, "moshe", "levy", "Programmers", 202}
};

/* global variable - employee of the day */
struct employee employee_of_the_day;

void copy_employee(struct employee *from, struct employee *to) {
int rc; /* contain mutex lock/unlock results */

/*lock the mutex, to assure exclusive access to 'a' and 'b' */
rc = pthread_mutex_lock(&a_mutex);

to->number = from->number;
to->id = from->id;
strcpy(to->first_name, from->first_name);
strcpy(to->last_name, from->last_name);
strcpy(to->department, from->department);
to->room_number = from->room_number;

/* unlock mutex */
rc = pthread_mutex_unlock(&a_mutex);
}

/* function to be executed by the variable setting threads thread */
void *do_loop(void *data) {
int my_num = *((int*)data);

while(1) {
/* set employee of the day to be the one with number 'my_num' */
copy_employee(&employees[my_num-1], &employee_of_the_day);
}
}

/* program's execution begins in main */

int main(int argc, char *argv[]) {
int i;
int thr_id1;
int thr_id2;
pthread_t p_thread1;
pthread_t p_thread2;
int num1 = 1;
int num2 = 2;
struct employee eotd;
struct employee *worker;

/* initialize employee of the day to first 1 */
copy_employee(&employees[0], &employee_of_the_day);

/* create a new thread that will execute 'do_loop()' with '1' */
thr_id1 = pthread_create(&p_thread1, NULL, do_loop, (void*)&num1);

/* create a new thread that will execute 'do_loop()' with '2' */
thr_id2 = pthread_create(&p_thread2, NULL, do_loop, (void*)&num2);

/* run a loop that verifies integrity of 'employee of the day' many */
/* many times.... */
for (i = 0; i < 600000; i++) {
/* save contents of 'employee of the day' to local 'worker' */
copy_employee(&employee_of_the_day, &eotd);
worker = &employees[eotd.number-1];

/* compare employees */
if (eotd.id != worker->id) {
printf("mismatching 'id', %d != %d (loop '%d')\n",
eotd.id, worker->id, i);
exit(0);
}
if (strcmp(eotd.first_name, worker->first_name) != 0) {
printf("mismatching 'first_name' , %s != %s (loop '%d')\n",
eotd.first_name, worker->first_name, i);
exit(0);
}
if (strcmp(eotd.last_name, worker->last_name) != 0) {
printf("mismatching 'last_name' , %s != %s (loop '%d')\n",
eotd.last_name, worker->last_name, i);
exit(0);
}
if (strcmp(eotd.department, worker->department) != 0) {
printf("mismatching 'department' , %s != %s (loop '%d')\n",
eotd.department, worker->department, i);
exit(0);
}
if (eotd.room_number != worker->room_number) {
printf("mismatching 'room_number' , %d != %d (loop '%d')\n",
eotd.room_number, worker->room_number, i);
exit(0);
}
}

printf("Glory, employees contents was always consistent\n");
return 0;
}

我基本上想确认一下,在main的for循环中,有以下语句

copy_employee(&employee_of_the_day, &eotd);

可以由 3 个线程中的任何一个执行;我对吗?随后的比较显然不是原子的,这一事实引起了一些困惑。对此的任何澄清/更正都会非常有帮助。

顺便问一下,关于 C 多线程教程有什么好的推荐吗?

非常感谢!

最佳答案

不,main 中的代码仅由一个线程执行。

使用互斥体确保 copy_employee 函数的原子性。

关于c - C 中的多线程,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10126335/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com