c - c 中函数切换中的 ";" token 错误之前预期为 "{"

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已关闭。这个问题是 not reproducible or was caused by typos 。目前不接受答案。

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我正在学习 C 语言作为我的第一语言。我正在使用 gcc 代码块编译器。我试图使用 switch-case观看视频后的发言。我收到一个错误，;之前预计 {声明 token 。我尝试过但找不到任何错误。谁能帮我解决这个问题吗？

#include<stdio.h>
#include<conio.h>
int main()
{
    int b,sum,avg,multi,choise,s[5],a[3];
    printf("Please select any option\n");
    printf("1. I want addition of numbers.\n");
    printf("2. I want to take average of numbers.\n");
    printf(" 3. I want the multiplication table of a number.\n");
    printf("4. Exit\n");

    Switch(choise)
    {
        case 1:
            printf("You have selected the 1st option,\n");
            printf("Please enter any 5 numbers you want to add.\n");
            gets(s);
            sum=s[0]+s[1]+s[2]+s[3]+s[4];
            printf("The sum of the numbers you entered is %d",sum);
            break;
        case 2:
            printf("You have selected the 2nd option,\n");
            printf("Enter any 3 numbers to take average of them.\n");
            gets(a);
            avg=a[0]+a[1]+a[2]/3;
            printf("The average of the three numbers you entered is %d",avg);
            break;
        case 3:
            printf("You have selected the 3rd option,\n");
            printf("Please enter the number you want the  multiplication table of,\n");
            scanf("%d",&multi);
            for(b=1;b<=10;b++)
            {
            printf("%d * %d = %d\n",multi,b,multi*b);
            }
            break;
        default:
            printf("invalid input.\n");
            break;
    }
}

Answer 1

关键字是switch，而不是Switch。您使编译器误认为您正在调用函数，因此在行后缺少语句终止符，如下所示:

Switch(choice);