c# - 如何检查所有两个对象的属性是否相等，包括派生属性？

Question

假设我有这三个类:

class Person
{
    public string FirstName { get; set; }
    public string LastName { get; set; }
    public int IdNumber { get; set; }
    public string Address { get; set; }

    // Constructor and methods.
}

class Employee : Person
{
    public byte SalaryPerHour { get; set; }
    public byte HoursPerMonth { get; set; }

    // Constructor and methods.
}

class Seller : Employee
{
    public short SalesGoal { get; set; }
    public bool MetSaleGoleLastYear { get; set; }

    // Constructor and methods.
}

我会实现 IEquatable<T>像这样:

public bool Equals(Person other)
{
    if (other == null) return false;
    return FirstName == other.FirstName
        && LastName == other.LastName
        && IdNumber == other.IdNumber
        && Address == other.Address;
}

public bool Equals(Employee other)
{
    if (other == null) return false;
    return FirstName == other.FirstName
        && LastName == other.LastName
        && IdNumber == other.IdNumber
        && Address == other.Address
        && SalaryPerHour == other.SalaryPerHour
        && HoursPerMonth == other.HoursPerMonth;
}

public bool Equals(Seller other)
{
    if (other == null) return false;
    return FirstName == other.FirstName
        && LastName == other.LastName
        && IdNumber == other.IdNumber
        && Address == other.Address
        && SalaryPerHour == other.SalaryPerHour
        && HoursPerMonth == other.HoursPerMonth
        && SalesGoal == other.SalesGoal
        && MetSaleGoleLastYear == other.MetSaleGoleLastYear;
}

现在，如您所见，类在继承链中的位置越靠下，我需要检查的属性就越多。例如，如果我继承自其他人编写的类，我还需要查看类代码以找到它的所有属性，这样我就可以使用它们来检查值是否相等。这对我来说听起来很奇怪。难道没有更好的方法吗？

Answer 1

使用基础。短得多。

public bool Equals(Seller other)
{
    if (other == null) return false;
    return base.Equals(other)
    && SalesGoal == other.SalaryPerHour;
    && MetSaleGoleLastYear == other.HoursPerMonth;
}