c - 在 C 中将字符串从数组传递到函数指针

Question

有人可以帮我解决我看不到的代码问题吗？我有一个要显示的字符串数组。一个递增和递减并希望将字符串传递给函数的变量。问题是我想要的整个字符串没有被传递

即ucMainMenu = 1 MenuString[1] = "TIME"DisplayString("TIME")

const char MenuString[6][8] = {"UNITS", "TIME", "DATE", "PRINT", "BTOOTH", "SERVICE"};

void main
{
   ucMainMenu++; //variable changing
   DisplayString(MenuString[ucMainMenu]);  //look up variable in array pass string to function
}

void DisplayString(char *cDisplayString)
{
 //do stuff with string
}

Answer 1

试试这个:

const char MenuString[6][8] = {"UNITS", "TIME", "DATE", "PRINT", "BTOOTH", "SERVICE"};

void DisplayString(const char *cDisplayString)
{
 //do stuff with string
    printf("%s", cDisplayString);
}

int main(int argc, char * argv[]){

    int ucMainMenu = 1;
    DisplayString(MenuString[ucMainMenu]);  //look up variable in array pass string to function

    getchar();

}

了解 C 中的初始化 here

希望对你有帮助!