c - 二维指针数组到二维数组

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如何转换

char *s[]={
           "to err is human",
           "but to really mess things up ",
           "one needs to know c!!"
           };  

至

char s[3][50]={
           "to err is human",
           "but to really mess things up ",
           "one needs to know c!!"
           };

Answer 1

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main(void){
    char *s[]={
        "to err is human",
        "but to really mess things up ",
        "one needs to know c!!"
    };
    int i, size = sizeof(s)/sizeof(*s);
    char ns[size][50];//or use malloc, E.g next line
    //char (*ns)[50] = calloc(size, sizeof(char[50]));
    for(i=0;i<size;++i){
        memset(ns[i], 0, 50);//unnecessary if you use the calloc
        strcpy(ns[i], s[i]);
        //printf("%s\n", ns[i]);
    }
/*
    char ns[3][50]= {
        "to err is human",
        "but to really mess things up ",
        "one needs to know c!!"
    };
*/
    return 0;
}