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c - 如何扩展C程序以获得所有核心的CPU使用率

转载 作者:行者123 更新时间:2023-11-30 19:45:41 24 4
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我有一个程序可以计算所有核心的平均 CPU 使用率。我想扩展该程序以分别获取所有内核的 cpu 使用情况。我不知道如何单独为每个核心执行此操作。谢谢。

/proc/stat 的开头如下:

cpu  3698413 14728645 5722454 10134230 69449 0 1223 0 0 0
cpu0 976719 3443648 1547164 2603386 19834 0 411 0 0 0
cpu1 919933 3875010 1438785 2355286 17272 0 373 0 0 0
cpu2 989581 3082865 1559116 2922304 18621 0 169 0 0 0
cpu3 812180 4327122 1177389 2253254 13722 0 270 0 0 0

我计算平均值的程序:

#include <stdlib.h>
#include <stdio.h>
#include <stdarg.h>
#include <unistd.h>

#define PROCSTATFILE "/proc/stat"

void eprintf(const char *fmt, ...) {
va_list ap;
va_start(ap, fmt);
vfprintf(stderr, fmt, ap);
va_end(ap);
exit(EXIT_FAILURE);
}

double cpuusage(void) {
char buf[BUFSIZ];
static unsigned long long lastuser, lastnice, lastsystem, lastidle;
unsigned long long user, nice, system, idle;
unsigned long long total;
double percent;
FILE *fp;

if (lastuser && lastnice && lastsystem && lastidle) {
fp = fopen(PROCSTATFILE, "r");
if (!fp)
eprintf("failed to open %s\n", PROCSTATFILE);
fgets(buf, BUFSIZ, fp);
sscanf(buf, "cpu %llu %llu %llu %llu", &user, &nice, &system, &idle);
fclose(fp);

percent = 0;
total = 0;
total += (user - lastuser);
total += (nice - lastnice);
total += (system - lastsystem);
percent = total;
total += (idle - lastidle);
percent /= total;
percent *= 100;
}

fp = fopen(PROCSTATFILE, "r");
if (!fp)
eprintf("failed to open %s\n", PROCSTATFILE);
fgets(buf, BUFSIZ, fp);
sscanf(buf, "cpu %llu %llu %llu %llu", &lastuser, &lastnice, &lastsystem, &lastidle);
fclose(fp);

return percent;
}

int main(void) {
while (1) {
printf("cpu usage:%f\n", cpuusage());
sleep(1);
}

return EXIT_SUCCESS;
}

最佳答案

解决方案如下:

#include <stdlib.h>
#include <stdio.h>
#include <stdarg.h>
#include <string.h>
#include <unistd.h>
#include <sys/types.h>
#include <sys/sysinfo.h>

#define PROCSTATFILE "/proc/stat"

void eprintf(const char *fmt, ...) {
va_list ap;
va_start(ap, fmt);
vfprintf(stderr, fmt, ap);
va_end(ap);
exit(EXIT_FAILURE);
}

void *emalloc(size_t size) {
void *p;

p = malloc(size);
if (!p)
eprintf("out of memory\n");
return p;
}

int cpucount(void) {
int i;
FILE *fp;
char buf[BUFSIZ];

fp = fopen(PROCSTATFILE, "r");
if (!fp)
eprintf("can't open %s\n", PROCSTATFILE);
fgets(buf, BUFSIZ, fp);
for (i = 0; fgets(buf, BUFSIZ, fp); i++)
if (!!strncmp("cpu", buf, 3))
break;

fclose(fp);

return i;
}

double *cpuusage(void) {
int i;
char buf[BUFSIZ];
int cpus;
int cpuid;
int r;
static unsigned long long *lastuser, *lastnice, *lastsystem, *lastidle;
unsigned long long *user, *nice, *system, *idle;
unsigned long long total;
static double *percent;
FILE *fp;

cpus = cpucount();

if (!lastuser)
lastuser = emalloc(cpus * sizeof(long long));
if (!lastnice)
lastnice = emalloc(cpus * sizeof(long long));
if (!lastsystem)
lastsystem = emalloc(cpus * sizeof(long long));
if (!lastidle)
lastidle = emalloc(cpus * sizeof(long long));

user = emalloc(cpus * sizeof(long long));
nice = emalloc(cpus * sizeof(long long));
system = emalloc(cpus * sizeof(long long));
idle = emalloc(cpus * sizeof(long long));

if (!percent)
percent = calloc((cpus + 1), sizeof(double));

fp = fopen(PROCSTATFILE, "r");
if (!fp)
eprintf("can't open %s\n", PROCSTATFILE);
fgets(buf, BUFSIZ, fp);
for (i = 0; i < cpus; i++) {
if (lastuser[i] && lastnice[i] && lastsystem[i] && lastidle[i]) {
fgets(buf, BUFSIZ, fp);
r = sscanf(buf, "cpu%d %llu %llu %llu %llu",
&cpuid, &user[i], &nice[i], &system[i], &idle[i]);
if (r < 5)
break;

percent[i] = i;
total = i;
total += (user[i] - lastuser[i]);
total += (nice[i] - lastnice[i]);
total += (system[i] - lastsystem[i]);
percent[i] = total;
total += (idle[i] - lastidle[i]);
percent[i] /= total;
percent[i] *= 100;
}
}
free(user);
free(nice);
free(system);
free(idle);
fclose(fp);

fp = fopen(PROCSTATFILE, "r");
if (!fp)
eprintf("can't open %s\n", PROCSTATFILE);
fgets(buf, BUFSIZ, fp);
for (i = 0; i < 4; i++) {
fgets(buf, BUFSIZ, fp);
r = sscanf(buf, "cpu%d %llu %llu %llu %llu",
&cpuid, &lastuser[i], &lastnice[i], &lastsystem[i], &lastidle[i]);
if (r < 5)
break;
}
fclose(fp);

return percent;
}

int main(void) {
int i;
double *percent;

while (1) {
percent = cpuusage();

for (i = 0; percent[i]; i++)
printf("cpu%d:%.2f%%\n", i, percent[i]);
sleep(1);
}

return EXIT_SUCCESS;
}

关于c - 如何扩展C程序以获得所有核心的CPU使用率,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26001516/

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