c - 如何将位域及其内部的位传递给函数

Question

对于微 Controller ，您通常有一个寄存器及其位字段版本，使您能够单独访问每个引脚

假设我有来自两个位域的两个对象

struct {
        unsigned a_A:1;
        unsigned b_A:1;
        unsigned c_A:1;
        unsigned d_A:1;
        unsigned e_A:1;
        unsigned f_A:1;
        unsigned g_A:1;
        unsigned h_A:1;
        }A;
struct {
        unsigned a_B:1;
        unsigned b_B:1;
        unsigned c_B:1;
        unsigned d_B:1;
        unsigned e_B:1;
        unsigned f_B:1;
        unsigned g_B:1;
        unsigned h_B:1;
        }B;

如何构建一个接受位域及其位作为参数的函数就像

void my_func(bitfield,bit_name)

bit_name 应根据位域的每种类型而变化

Answer 1

怎么样

void my_func(unsigned a_B);
...
void my_func(unsigned h_B);

并调用它:

my_func(B.a_B);
...
my_func(B.h_B);