javascript - 在时间格式 hh :mm:ss 的数组中查找时间总和

Question

我有这段代码可以正确找到 hh:mm 格式的总和我很难将其转换为 hh:mm:ss 格式显然，所有内容都应正确舍入。

这是我希望使用的数组格式，但代码显然仅适用于 ["00", "10"] 作为示例

const array = [
  ["00", "00", "09"],
  ["00", "00", "09"],
  ["00", "00", "04"],
  ["00", "00", "02"],
  ["00", "00", "21"],
  ["00", "00", "14"],
  ["00", "00", "26"],
  ["00", "00", "02"],
  ["00", "00", "14"],
  ["00", "00", "10"],
  ["00", "00", "48"],
  ["00", "00", "12"],
  ["00", "00", "09"],
  ["00", "00", "09"]
]

var mins = 0;
var hrs = 0;

if (array == null) {
  mins = Number(t1[1]) + Number(t2[1]);
  hrs = Math.floor(parseInt(mins / 60));
  hrs = Number(t1[0]) + Number(t2[0]) + hrs;
} else {
  $.each(array, function(key) {
    mins += Number(array[key][1]);
    hrs = Math.floor(parseInt(mins / 60));
    hrs += Number(array[key][0]) + hrs;
  });
}

console.log(mins, hrs)

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

t1 和 t2 在这种情况下只是将 2 个单独的值加在一起，然后就有一堆这些值的数组。两者都应该工作正常。

也请帮我在这里正确添加秒数。

Answer 1

您可以获得秒数，将所有值相加并构建一个新的总和字符串。

function sumTime(t1, t2, array = []) {
    var times = [3600, 60, 1],
        sum = [t1, t2, ...array]
            .map(s => s.split(':').reduce((s, v, i) => s + times[i] * v, 0))
            .reduce((a, b) => a + b, 0);

    return times
        .map(t => [Math.floor(sum / t), sum %= t][0])
        .map(v => v.toString().padStart(2, 0))
        .join(':');
}

console.log(sumTime("01:02:03", "04:57:57"));
console.log(sumTime("00:00:09", "00:00:09", ["00:00:04", "00:00:02", "00:00:21", "00:00:14", "00:00:26", "00:00:02", "00:00:14", "00:00:10", "00:00:48", "00:00:12", "00:00:09", "00:00:09"]));

ES5

function sumTime(t1, t2, array) {
    var times = [3600, 60, 1],
        sum = [t1, t2].filter(Boolean).concat(array || [])
            .map(function (s) {
                return s
                    .split(':') // omit this line for splitted values ['02', '04', '45']
                    .reduce(function (s, v, i) {
                        return s + times[i] * v;
                    }, 0);
            })
            .reduce(function (a, b) { return a + b; }, 0);

    return times
        .map(function (t) {
            var value = Math.floor(sum / t);
            sum %= t;
            return value;
        })
        .map(function (v) {
            return v.toString().padStart(2, 0);
         })
        .join(':');
}


console.log(sumTime("01:02:03", null));
console.log(sumTime(null, "04:57:57"));
console.log(sumTime(null, null, ["01:02:03", "04:57:57"]));
console.log(sumTime("00:00:09", "00:00:09", ["00:00:04", "00:00:02", "00:00:21", "00:00:14", "00:00:26", "00:00:02", "00:00:14", "00:00:10", "00:00:48", "00:00:12", "00:00:09", "00:00:09"]));

使用拆分数组。

function sumTime(t1, t2, array) {
    var times = [3600, 60, 1],
        sum = [t1, t2].filter(Boolean).concat(array || [])
            .map(function (s) {
                return s
                    //.split(':') // omit this line for splitted values ['02', '04', '45']
                    .reduce(function (s, v, i) {
                        return s + times[i] * v;
                    }, 0);
            })
            .reduce(function (a, b) { return a + b; }, 0);

    return times
        .map(function (t) {
            var value = Math.floor(sum / t);
            sum %= t;
            return value;
        })
        .map(function (v) {
            return v.toString().padStart(2, 0);
         })
        .join(':');
}

console.log(sumTime(["01", "02", "03"], null));
console.log(sumTime(null, ["04", "57", "57"]));
console.log(sumTime(null, null, [["01", "02", "03"], ["04", "57", "57"]]));
console.log(sumTime(["00", "00", "09"], ["00", "00", "09"], [["00", "00", "04"], ["00", "00", "02"], ["00", "00", "21"], ["00", "00", "14"], ["00", "00", "26"], ["00", "00", "02"], ["00", "00", "14"], ["00", "00", "10"], ["00", "00", "48"], ["00", "00", "12"], ["00", "00", "09"], ["00", "00", "09"]]));